1 #include 2- void foo (const char* s) { const int* p = (int*) (s+1); int i=3; while(i){ printf("%c", *((char )p)); p++; i--; } 9. 10 } 11- int main() { 12 char spO = "1159456789"; foo (sp); return 0;...


Need explanation of this code respect to the output


1 #include <stdio.h><br>2- void foo (const char* s) {<br>const int* p = (int*) (s+1);<br>int i=3;<br>while(i){<br>printf(

Extracted text: 1 #include 2- void foo (const char* s) { const int* p = (int*) (s+1); int i=3; while(i){ printf("%c", *((char )p)); p++; i--; } 9. 10 } 11- int main() { 12 char spO = "1159456789"; foo (sp); return 0; 13 14 15 } 159 .Program finished with exit code o 3456 78

Jun 05, 2022
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