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11/10/2020 MyOpenMath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 1/6 Chapter 8 Confidence Intervals (Mean) Makenzie Lee Question 1 0/1 pt 3 98 Question 2 0/1 pt 3 98 Question 3 0/1 pt 3 99 Question 4 0/1 pt 3 99 Question 5 0/1 pt 3 99 Assume that a sample is used to estimate a population mean . Find the 80% confidence interval for a sample of size 633 with a mean of 78.1 and a standard deviation of 21.3. Enter your answer as a tri- linear inequality accurate to 3 decimal places.<>< question="" help:="" μ="" μ="" message="" instructor="" assume="" that="" a="" sample="" is="" used="" to="" estimate="" a="" population="" mean="" .="" find="" the="" 99.5%="" confidence="" interval="" for="" a="" sample="" of="" size="" 1000="" with="" a="" mean="" of="" 38.4="" and="" a="" standard="" deviation="" of="" 21.9.="" enter="" your="" answer="" as="" a="" tri-="" linear="" inequality="" accurate="" to="" 3="" decimal="" places.=""><>< question="" help:="" μ="" μ="" message="" instructor="" karen="" wants="" to="" advertise="" how="" many="" chocolate="" chips="" are="" in="" each="" big="" chip="" cookie="" at="" her="" bakery.="" she="" randomly="" selects="" a="" sample="" of="" 41="" cookies="" and="" finds="" that="" the="" number="" of="" chocolate="" chips="" per="" cookie="" in="" the="" sample="" has="" a="" mean="" of="" 19.5="" and="" a="" standard="" deviation="" of="" 3.7.="" what="" is="" the="" 90%="" confidence="" interval="" for="" the="" number="" of="" chocolate="" chips="" per="" cookie="" for="" big="" chip="" cookies?="" enter="" your="" answers="" accurate="" to="" one="" decimal="" place="" (because="" the="" sample="" statistics="" are="" reported="" accurate="" to="" one="" decimal="" place).=""><>< question help: μ message instructor a botanist wishes to estimate the typical number of seeds for a certain fruit. she samples 71 specimens and counts the number of seeds in each. use her sample results (mean = 40.9, standard deviation = 5.2) to find the 99% confidence interval for the number of seeds for the species. enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.  99% c.i. = question help: message instructor https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=0-149858-2659-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=1-171261-7987-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=2-46555-2294-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=3-149863-21-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 2/6 question 6 0.2/1 pt 1-3 99 question 7 0.2/1 pt 1-3 99 in a survey, 24 people were asked how much they spent on their child's last birthday gift. the results were roughly bell-shaped with a mean of $42.3 and standard deviation of $13.3. estimate how much a typical parent would spend on their child's birthday gift (use a 99% confidence level). give your answers to 3 decimal places. express your answer in the format of     error.  $ $ question help: x̄ ± ± message instructor a researcher is interested in finding a 98% confidence interval for the mean number minutes students are concentrating on their professor during a one hour statistics lecture. the study included 95 students who averaged 38.8 minutes concentrating on their professor during the hour lecture. the standard deviation was 12.4 minutes. a. to compute the confidence interval use a distribution. b. with 98% confidence the population mean minutes of concentration is between  and   minutes. c. if many groups of 95 randomly selected members are studied, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean minutes of concentration and about percent will not contain the true population mean minutes of concentration.    question help: t message instructor https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=4-149865-2902-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=5-149550-6366-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 3/6 question 8 0.2/1 pt 1-3 99 question 9 0/1 pt 3 99 a fitness center is interested in finding a 90% confidence interval for the mean number of days per week that americans who are members of a fitness club go to their fitness center. records of 252 members were looked at and their mean number of visits per week was 3.5 and the standard deviation was 1.6. round answers to 3 decimal places where possible. a. to compute the confidence interval use a distribution. b. with 90% confidence the population mean number of visits per week is between  and   visits. c. if many groups of 252 randomly selected members are studied, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean number of visits per week and about percent will not contain the true population mean number of visits per week.    question help: t message instructor a fitness center is interested in finding a 90% confidence interval for the mean number of days per week that americans who are members of a fitness club go to their fitness center. records of 214 members were looked at and their mean number of visits per week was 3.3 and the standard deviation was 2.7. a. to compute the confidence interval use a distribution. b. with 90% confidence the population mean number of visits per week is between  and   visits. c. if many groups of 214 randomly selected members are studied, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean number of visits per week and about percent will not contain the true population mean number of visits per week.    question help: t message instructor https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=6-171209-5731-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=7-149501-6678-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 4/6 question 10 0/1 pt 3 99 question 11 0.2/1 pt 2-3 99 the body temperatures in degrees fahrenheit of a sample of adults in one small town are: 96.4 97.2 99.2 98.6 98.3 99.4 99.6 98.1 assume body temperatures of adults are normally distributed. based on this data, find the 95% confidence interval of the mean body temperature of adults in the town. enter your answer as an open- interval (i.e., parentheses) accurate to 3 decimal places. assume the data is from a normally distributed population. 95% c.i. =   question help: message instructor the body temperatures in degrees fahrenheit of a sample of adults in one small town are: 98.6 99.9 96.6 98.5 96.8 97.6 96.5 98.8 96.3 96.7 98.7 assume body temperatures of adults are normally distributed. based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. enter your answer as an open- interval (i.e., parentheses) accurate to 3 decimal places. assume the data is from a normally distributed population. 98% c.i. =   question help: message instructor https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=8-171204-7677-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=9-99458-6780-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 5/6 question 12 0.2/1 pt 2-3 99 you are interested in finding a 98% confidence interval for the average commute that non- residential students have to their college. the data below show the number of commute miles for 13 randomly selected non-residential college students. 13 18 24 7 7 23 6 19 7 9 23 16 5 a. to compute the confidence interval use a distribution. b. with 98% confidence the population mean commute for non-residential college students is between  and   miles. c. if many groups of 13 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of  commute miles.    question help: t message instructor a psychiatrist is interested in finding a 95% confidence interval for the tics per hour exhibited by children with tourette syndrome. the data below show the tics in an observed hour for 15 randomly selected children with tourette syndrome. round answers to 3 decimal places where possible. 8 5 12 6 8 2 0 6 9 9 3 3 4 3 4 a. to compute the confidence interval use a distribution. b. with 95% confidence the population mean number of tics per hour that children with tourette syndrome exhibit is between  and   . c. if many groups of 15 randomly selected  children with tourette syndrome are observed, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean number of tics per hour and about percent will not contain the true population mean number of tics per hour.    t https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=10-149598-3991-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 6/6 question 13 0.2/1 pt 2-3 99 question help: message instructor you are interested in finding a 90% confidence interval for the average number of days of class that college students miss each year. the data below show the number of missed days for 11 randomly selected college students. round answers to 3 decimal places where possible. 10 5 5 10 11 2 5 10 9 12 4 a. to compute the confidence interval use a distribution. b. with 90% confidence the population mean number of days of class that college students miss is between  and   days. c. if many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. about percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.    question help: t message instructor https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=11-154644-4138-5938124-2&to=instr https://www.myopenmath.com/msgs/msglist.php?cid=82917&add=new"eq=12-154643-5218-5938124-2&to=instr 11/10/2020 myopenmath https://www.myopenmath.com/assess2/?cid=82917&aid=5938125#/print 1/8 chapter 8: confidence intervals (proportions) makenzie lee question 1 0/1 pt 3 99 question 2 0/1 pt 3 99 question 3 0/1 pt 3 99 139 students at a college were asked whether they had completed their required english 101 course, and 78 students said "yes". find the best point estimate for the proportion of students at the college who have completed their required english 101 course. round to four decimal places. question help: message instructor a poll of 1105 u.s. adults found that 47% regularly used facebook as a news source. find the margin of error and confidence interval for the percentage of u.s. adults who regularly use facebook as a news source, at the 90% level of confidence. round all answers to 2 decimal places. margin of error (as a percentage): confidence interval: % to % find the margin of error and confidence interval for the percentage of u.s question="" help:="" μ="" message="" instructor="" a="" botanist="" wishes="" to="" estimate="" the="" typical="" number="" of="" seeds="" for="" a="" certain="" fruit.="" she="" samples="" 71="" specimens="" and="" counts="" the="" number="" of="" seeds="" in="" each.="" use="" her="" sample="" results="" (mean="40.9," standard="" deviation="5.2)" to="" find="" the="" 99%="" confidence="" interval="" for="" the="" number="" of="" seeds="" for="" the="" species.="" enter="" your="" answer="" as="" an="" open-interval="" (i.e.,="" parentheses)="" accurate="" to="" 3="" decimal="" places. ="" 99%="" c.i.="Question" help:="" message="" instructor="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=0-149858-2659-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=1-171261-7987-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=2-46555-2294-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=3-149863-21-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938124#/print" 2/6="" question="" 6="" 0.2/1="" pt="" 1-3="" 99="" question="" 7="" 0.2/1="" pt="" 1-3="" 99="" in="" a="" survey,="" 24="" people="" were="" asked="" how="" much="" they="" spent="" on="" their="" child's="" last="" birthday="" gift.="" the="" results="" were="" roughly="" bell-shaped="" with="" a="" mean="" of="" $42.3="" and="" standard="" deviation="" of="" $13.3.="" estimate="" how="" much="" a="" typical="" parent="" would="" spend="" on="" their="" child's="" birthday="" gift="" (use="" a="" 99%="" confidence="" level).="" give="" your="" answers="" to="" 3="" decimal="" places.="" express="" your="" answer="" in="" the="" format="" of=""  =""   error. ="" $="" $="" question="" help:="" x̄="" ±="" ±="" message="" instructor="" a="" researcher="" is="" interested="" in="" finding="" a="" 98%="" confidence="" interval="" for="" the="" mean="" number="" minutes="" students="" are="" concentrating="" on="" their="" professor="" during="" a="" one="" hour="" statistics="" lecture.="" the="" study="" included="" 95="" students="" who="" averaged="" 38.8="" minutes="" concentrating="" on="" their="" professor="" during="" the="" hour="" lecture.="" the="" standard="" deviation="" was="" 12.4="" minutes.="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 98%="" confidence="" the="" population="" mean="" minutes="" of="" concentration="" is="" between=""  and=""  ="" minutes.="" c. if="" many="" groups="" of="" 95="" randomly="" selected="" members="" are="" studied,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" minutes="" of="" concentration="" and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" minutes="" of="" concentration. =""  ="" question="" help:="" t="" message="" instructor="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=4-149865-2902-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=5-149550-6366-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938124#/print" 3/6="" question="" 8="" 0.2/1="" pt="" 1-3="" 99="" question="" 9="" 0/1="" pt="" 3="" 99="" a="" fitness="" center="" is="" interested="" in="" finding="" a="" 90%="" confidence="" interval="" for="" the="" mean="" number="" of="" days="" per="" week="" that="" americans="" who="" are="" members="" of="" a="" fitness="" club="" go="" to="" their="" fitness="" center.="" records="" of="" 252="" members="" were="" looked="" at="" and="" their="" mean="" number="" of="" visits="" per="" week="" was="" 3.5="" and="" the="" standard="" deviation="" was="" 1.6.="" round="" answers="" to="" 3="" decimal="" places="" where="" possible.="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 90%="" confidence="" the="" population="" mean="" number="" of="" visits="" per="" week="" is="" between=""  and=""  ="" visits.="" c. if="" many="" groups="" of="" 252="" randomly="" selected="" members="" are="" studied,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" number="" of="" visits="" per="" week="" and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" number="" of="" visits="" per="" week. =""  ="" question="" help:="" t="" message="" instructor="" a="" fitness="" center="" is="" interested="" in="" finding="" a="" 90%="" confidence="" interval="" for="" the="" mean="" number="" of="" days="" per="" week="" that="" americans="" who="" are="" members="" of="" a="" fitness="" club="" go="" to="" their="" fitness="" center.="" records="" of="" 214="" members="" were="" looked="" at="" and="" their="" mean="" number="" of="" visits="" per="" week="" was="" 3.3="" and="" the="" standard="" deviation="" was="" 2.7.="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 90%="" confidence="" the="" population="" mean="" number="" of="" visits="" per="" week="" is="" between=""  and=""  ="" visits.="" c. if="" many="" groups="" of="" 214="" randomly="" selected="" members="" are="" studied,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" number="" of="" visits="" per="" week="" and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" number="" of="" visits="" per="" week. =""  ="" question="" help:="" t="" message="" instructor="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=6-171209-5731-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=7-149501-6678-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938124#/print" 4/6="" question="" 10="" 0/1="" pt="" 3="" 99="" question="" 11="" 0.2/1="" pt="" 2-3="" 99="" the="" body="" temperatures="" in="" degrees="" fahrenheit="" of="" a="" sample="" of="" adults="" in="" one="" small="" town="" are:="" 96.4="" 97.2="" 99.2="" 98.6="" 98.3="" 99.4="" 99.6="" 98.1="" assume="" body="" temperatures="" of="" adults="" are="" normally="" distributed.="" based="" on="" this="" data,="" find="" the="" 95%="" confidence="" interval="" of="" the="" mean="" body="" temperature="" of="" adults="" in="" the="" town.="" enter="" your="" answer="" as="" an="" open-="" interval="" (i.e.,="" parentheses)="" accurate="" to="" 3="" decimal="" places. assume="" the="" data="" is="" from="" a="" normally="" distributed="" population.="" 95%="" c.i.=" " question="" help:="" message="" instructor="" the="" body="" temperatures="" in="" degrees="" fahrenheit="" of="" a="" sample="" of="" adults="" in="" one="" small="" town="" are:="" 98.6="" 99.9="" 96.6="" 98.5="" 96.8="" 97.6="" 96.5="" 98.8="" 96.3="" 96.7="" 98.7="" assume="" body="" temperatures="" of="" adults="" are="" normally="" distributed.="" based="" on="" this="" data,="" find="" the="" 98%="" confidence="" interval="" of="" the="" mean="" body="" temperature="" of="" adults="" in="" the="" town.="" enter="" your="" answer="" as="" an="" open-="" interval="" (i.e.,="" parentheses)="" accurate="" to="" 3="" decimal="" places. assume="" the="" data="" is="" from="" a="" normally="" distributed="" population.="" 98%="" c.i.=" " question="" help:="" message="" instructor="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=8-171204-7677-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=9-99458-6780-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938124#/print" 5/6="" question="" 12="" 0.2/1="" pt="" 2-3="" 99="" you="" are="" interested="" in="" finding="" a="" 98%="" confidence="" interval="" for="" the="" average="" commute="" that="" non-="" residential="" students="" have="" to="" their="" college.="" the="" data="" below="" show="" the="" number="" of="" commute="" miles="" for="" 13="" randomly="" selected="" non-residential="" college="" students.="" 13="" 18="" 24="" 7="" 7="" 23="" 6="" 19="" 7="" 9="" 23="" 16="" 5="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 98%="" confidence="" the="" population="" mean="" commute="" for="" non-residential="" college="" students="" is="" between=""  and=""  ="" miles.="" c. if="" many="" groups="" of="" 13="" randomly="" selected="" non-residential="" college="" students="" are="" surveyed,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" number="" of="" commute="" miles="" and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" number="" of=""  commute="" miles. =""  ="" question="" help:="" t="" message="" instructor="" a="" psychiatrist="" is="" interested="" in="" finding="" a="" 95%="" confidence="" interval="" for="" the="" tics="" per="" hour="" exhibited="" by="" children="" with="" tourette="" syndrome.="" the="" data="" below="" show="" the="" tics="" in="" an="" observed="" hour="" for="" 15="" randomly="" selected="" children="" with="" tourette="" syndrome.="" round="" answers="" to="" 3="" decimal="" places="" where="" possible.="" 8="" 5="" 12="" 6="" 8="" 2="" 0="" 6="" 9="" 9="" 3="" 3="" 4="" 3="" 4="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 95%="" confidence="" the="" population="" mean="" number="" of="" tics="" per="" hour="" that="" children="" with="" tourette="" syndrome="" exhibit="" is="" between=""  and=""  ="" .="" c. if="" many="" groups="" of="" 15="" randomly="" selected=""  children="" with="" tourette="" syndrome="" are="" observed,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" number="" of="" tics="" per="" hour and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" number="" of="" tics="" per="" hour. =""  ="" t="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=10-149598-3991-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938124#/print" 6/6="" question="" 13="" 0.2/1="" pt="" 2-3="" 99="" question="" help:="" message="" instructor="" you="" are="" interested="" in="" finding="" a="" 90%="" confidence="" interval="" for="" the="" average="" number="" of="" days="" of="" class="" that="" college="" students="" miss="" each="" year.="" the="" data="" below="" show="" the="" number="" of="" missed="" days="" for="" 11="" randomly="" selected="" college="" students.="" round="" answers="" to="" 3="" decimal="" places="" where="" possible.="" 10="" 5="" 5="" 10="" 11="" 2="" 5="" 10="" 9="" 12="" 4="" a.="" to="" compute="" the="" confidence="" interval="" use="" a="" distribution.="" b.="" with 90%="" confidence="" the="" population="" mean="" number="" of="" days="" of="" class="" that="" college="" students="" miss="" is="" between=""  and=""  ="" days.="" c. if="" many="" groups="" of="" 11="" randomly="" selected="" non-residential="" college="" students="" are="" surveyed,="" then="" a="" different="" confidence="" interval="" would="" be="" produced="" from="" each="" group.="" about="" percent="" of="" these="" confidence="" intervals="" will="" contain="" the="" true="" population="" mean="" number="" of="" missed="" class="" days="" and="" about="" percent="" will="" not="" contain="" the="" true="" population="" mean="" number="" of="" missed="" class="" days. =""  ="" question="" help:="" t="" message="" instructor="" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=11-154644-4138-5938124-2&to=instr" https://www.myopenmath.com/msgs/msglist.php?cid="82917&add=new"eq=12-154643-5218-5938124-2&to=instr" 11/10/2020="" myopenmath="" https://www.myopenmath.com/assess2/?cid="82917&aid=5938125#/print" 1/8="" chapter="" 8:="" confidence="" intervals="" (proportions)="" makenzie="" lee="" question="" 1="" 0/1="" pt="" 3="" 99="" question="" 2="" 0/1="" pt="" 3="" 99="" question="" 3="" 0/1="" pt="" 3="" 99="" 139="" students="" at="" a="" college="" were="" asked="" whether="" they="" had="" completed="" their="" required="" english="" 101="" course,="" and="" 78="" students="" said="" "yes".="" find="" the="" best="" point="" estimate="" for="" the="" proportion="" of="" students="" at="" the="" college="" who="" have="" completed="" their="" required="" english="" 101="" course.="" round="" to="" four="" decimal="" places.="" question="" help:="" message="" instructor="" a="" poll="" of="" 1105="" u.s.="" adults="" found="" that="" 47%="" regularly="" used="" facebook="" as="" a="" news="" source.="" find="" the="" margin="" of="" error="" and="" confidence="" interval="" for="" the="" percentage="" of="" u.s.="" adults="" who="" regularly="" use="" facebook="" as="" a="" news="" source,="" at="" the="" 90%="" level="" of="" confidence.="" round="" all="" answers="" to="" 2="" decimal="" places.="" margin="" of="" error="" (as="" a="" percentage):="" confidence="" interval:="" %="" to="" %="" find="" the="" margin="" of="" error="" and="" confidence="" interval="" for="" the="" percentage="" of="">
Answered Same DayNov 10, 2021

Answer To: 11/10/2020 MyOpenMath https://www.myopenmath.com/assess2/?cid=82917&aid=5938124#/print 1/6 Chapter 8...

Suraj answered on Nov 12 2021
137 Votes
Chapter 8 confidence intervals (Mean)
1.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

2.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

3.
Consider the given information,
The confidence interval for mean
Thus, substitute the val
ues and the confidence interval is given as follows:
Confidence interval

4.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

5.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

6.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

With 98% confidence the population mean minutes of concentration is between 35.793 and 41.806 minutes.
If many groups of 95 randomly selected members are studied, then a different confidence interval would be produced from each group. About 98% percent of these confidence intervals will contain the true population mean minutes of concentration and about 2% percent will not contain the true population mean minutes of concentration.
7.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

With 90% confidence the population mean minutes of concentration is between 3.334 and 3.666 minutes.
If many groups of 252 randomly selected members are studied, then a different confidence interval would be produced from each group. About 90% percent of these confidence intervals will contain the true population mean minutes of concentration and about 10% percent will not contain the true population mean minutes of concentration.
8.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

With 90% confidence the population mean minutes of concentration is between 2.995 and 3.605 minutes.
If many groups of 214 randomly selected members are studied, then a different confidence interval would be produced from each group. About 90% percent of these confidence intervals will contain the true population mean minutes of concentration and about 10% percent will not contain the true population mean minutes of concentration.
9.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

10.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

11.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

b. With 98% confidence the population mean commute for non-residential college students is between 8.263 and 18.957 miles.
c. If many groups of 13 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About 95% percent of these confidence intervals will contain the true population mean number of commute miles and about 5% percent will not contain the true population mean number of commute miles.
12.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

b. With 95% confidence the population mean number of tics per hour that children with Tourette syndrome exhibit is between 3.680 and 7.260.
c. If many groups of 15 randomly selected children with Tourette syndrome are observed, then a different confidence interval would be produced from each group. About 95% percent of these confidence intervals will contain the true population mean number of tics per hour and about 5% percent will not contain the true population mean number of tics per hour.
13.
Consider the given information,
The confidence interval for mean
Thus, substitute the values and the confidence interval is given as follows:
Confidence interval

b. With 90% confidence the population mean number of days of class that college students miss is between 5.690 and 9.390 days.
c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About 90% percent of these confidence intervals will contain the true population mean number of missed class days and about 10% percent will not contain...
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