12AP - Unit 2 Test - Electromagnetism XXXXXXXXXXpages Grade 12AP Physics 2020 – 2021 Name: _____________________________ Unit 2 Take-Home Test Assignment - Electromagnetism Instructions: 1. Answer all...

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12AP - Unit 2 Test - Electromagnetism 2020-2021.pages Grade 12AP Physics 2020 – 2021 Name: _____________________________ Unit 2 Take-Home Test Assignment - Electromagnetism Instructions: 1. Answer all questions clearly numbered on paper of your choice. 2. You may use a calculator, a writing implement and a ruler. 3. For quick reference, you can use the provided formula page (at the end of the test assignment). 4. Part marks may be assigned, but only if your work is shown. 5. Always remember to fully explain your reasoning. 6. This is due on Thursday, March 11th, 2021 (by end of day). 1. Examine the circuit shown below. (9 marks) (a) Determine the total equivalent capacitance for this complex circuit – show at least 2 steps in your simplification process. (5 mks) (b) Determine the total charge stored in the simplified equivalent circuit you found in part (a). (1 mk) (c) In a capacitor, the area of the plates is and the separation distance between capacitor plates is . Calculate the dielectric constant . (1.5 mk) (d) Describe how it is possible to halve the capacitance of a given capacitor without altering the area of the plates or the dielectric constant value. (1.5 mk) 2. A solenoid coil is connected to a strong DC voltage source as shown below. In addition a length of wire is suspended horizontally across the opening of the solenoid at the right side. The solenoid coil has a diameter of . (7 marks) (a) Label the ‘magnetic poles’ of the solenoid AND determine the direction of the current flowing in the wire coils of the solenoid (indicate it clearly on the diagram or provide a rough sketch in your answer). (2 mks) (b) A DC current of is passed through the wire suspended in front of the solenoid (at the right end) and it is 6.2 µF 2.45 m 2 0.28 mm κ 16.4 cm 64.5 A 36V 3 µF 1.5 µF 0.6 µF 2 µF 3 µF 3 µF / 29 pulled downwards with a force of . Label the direction of current flow in the wire (or in your rough sketch) AND determine the strength of the magnetic field B at the opening of the solenoid (where the wire passes). (3 mks) (c) If the current flowing through the wire suspended in front of the solenoid opening was switched to being AC current instead (the current in the solenoid remains DC), how would the wire across the opening of the solenoid behave? (2 mks) 3. A charged particle is fired directly towards a long, straight conducting wire that is fixed in place. The current in the wire is flowing upwards in the ‘Top View’ shown in the diagram and into this page in the ‘Side View’ diagram. The charge moves in the plane of the paper (in both diagrams) at high speed. (see diagram at the right). (7 marks) (a) Sketch in the magnetic field created by the wire (in both diagrams) and then describe the path taken by the particle as it approaches the wire. Explain briefly by referring to any forces, directions, and consequences to its motion and include a sketch of its motion on the diagram. Also, make sure to distinguish between the path(s) of positive, negative and neutral particles. (4 mks) (b) The magnetic field strength at a location r metres from conductor (measured perpendicular) with current I is given by the formula below (where is the vacuum permeability constant). If the magnetic field strength is at a distance of , determine the current flowing in the wire. (1.5 mks) where (c) Suppose the particle has a charge of , a mass of and is moving at a speed of towards the wire. Determine the magnetic force it experiences when it is at a distance of from the wire. (1.5 mks) 4. A rectangular current loop is placed between two large permanent magnets. The magnetic field flows downwards, perpendicular to the page and has a strength of . The loop is connected to the end of a shaft that can rotate around an axis in the plane of the page (and passes through the centre of the rectangular loop) and oriented horizontally. The current loop measures wide and tall. See the diagram below: (6 marks) 4.8 N µ 0 1.12T 5.2 cm B = µ 0 2π ⋅ I r µ 0 = 4π ×10 −7 T ⋅m A + 4.806 ×10 −19 C 3.308 ×10 −27 kg 2.25 ×108 m s 3.6 ×10 −4 m 2.88 T 16.4 cm 10.5 cm (a) Determine the magnetic flux, , passing through the current loop as shown in the diagram. (1.5 mks) (b) The loop is forced to rotate around the axis in a counter-clockwise direction as seen from the left side of the page looking to the right along the axis of rotation (bottom edge rises up and out of the page while the top descends below the page). It rotates with a period of . Determine the change in the magnetic flux through the loop once it has been rotated half- way through one complete revolution (that is, calculate ). (1.5 mk) (c) Determine the strength of the emf (voltage) created in the wire loop as a result of its forced rotation described above. (1.5 mk) (d) At the instant the loop is in the plane of the page (the diagram above), what direction will the induced current move in the loop while the emf (voltage) is being created? (clockwise or counter-clockwise) Explain your reasoning. (1.5 mks) Φ B 0.25 s ΔΦ B
Answered Same DaySep 27, 2021

Answer To: 12AP - Unit 2 Test - Electromagnetism XXXXXXXXXXpages Grade 12AP Physics 2020 – 2021 Name:...

Priyanka answered on Sep 27 2021
133 Votes
(a) Given Capacitor circuit:
Equivalent of series capacitor: +
Equivalent o
f parallel capacitor:
Step 1: simplifying series connections marked in above circuit

Step 2: Simplifying marked parallel combination

Step 3: above circuit simplified as

Fig. Simplified circuit
(b) Voltage (V)=36 V
Capacitance (C)...
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