Consider a constant-area mixer, as shown. The mass flow ratio between the cold and hot streams is 3, i.e., ṁ 15 ṁ 5 = 3. The gas properties are: cp15 = 1,004 J/kg ⋅ K, 𝛾15 = 1.4 cp5 = 1,156 J/kg ⋅...

Consider a constant-area mixer, as shown. The mass

flow ratio between the cold and hot streams is 3, i.e., ṁ 15

ṁ 5

= 3.

The gas properties are: cp15 = 1,004 J/kg ⋅ K, 𝛾15 = 1.4 cp5 =

1,156 J/kg ⋅ K and 𝛾5 = 1.33. The flow conditions in the inlet

to the mixer are:

pt5 = pt15 = 150 kPa, Tt15 = 500 K and Tt5 = 880 K.

Assuming the hot gas Mach number is M5 = 0.4,

calculate

(a) gas properties at the mixed exit, cp6M and 𝛾6M

(b) Mach number of the cold stream, M15

(c) area ratio, A15/A5

(d) total temperature at the mixed exit, Tt6M in K