8.28 LAB: Check if list is sorted Write the in_order() function, which has a list of integers as a parameter, and returns True if the integers are sorted (in order from low to high) or False...

Write the in_order() function, which has a list of integers as a parameter, and returns True if the integers are sorted (in order from low to high) or False otherwise. The program outputs "In order" if the list is sorted, or "Not in order" if the list is not sorted.

Ex: If the list passed to the in_order() function is [5, 6, 7, 8, 3], then the function returns False and the program outputs:

Ex: If the list passed to the in_order() function is [5, 6, 7, 8, 10], then the function returns True and the program outputs:

Note: Use a for loop.DO NOT use sorted() or sort().

this is the code im supposed to use

def in_order(nums):
    # Type your code here.

if __name__ == '__main__':
    # Test out-of-order example
    nums1 = [5, 6, 7, 8, 3]
    if in_order(nums1):
        print('In order')
    else:
        print('Not in order')

    # Test in-order example
    nums2 = [5, 6, 7, 8, 10]
    if in_order(nums2):
        print('In order')
    else:
        print('Not in order')