A manufacturer of car batteries claims that the life of the company's batteries in years is approximately normally distributed with a population variance of 0.81. A random sample of 10 of these...


A manufacturer of car batteries claims that the life of the company's batteries in years is approximately<br>normally distributed with a population variance of 0.81. A random sample of 10 of these batteries has a<br>variance of 1.44. You will test the claim that the population variance is more than 0.81 using an a =0.05<br>level of significance. The p-value for this test is 0.07. Make an appropriate conclusion.<br>O Reject the null hypothesis and conclude that the population variance is greater than 0.81.<br>O Fail to reject the null hypothesis and conclude that the population variance is less than or equal to 0.81.<br>O The test is inconclusive because the p-value is nearly 0.<br>One can not make a decision with the p-value alone. We need both a p-value and the value of test<br>statistic to make a conclusion.<br>

Extracted text: A manufacturer of car batteries claims that the life of the company's batteries in years is approximately normally distributed with a population variance of 0.81. A random sample of 10 of these batteries has a variance of 1.44. You will test the claim that the population variance is more than 0.81 using an a =0.05 level of significance. The p-value for this test is 0.07. Make an appropriate conclusion. O Reject the null hypothesis and conclude that the population variance is greater than 0.81. O Fail to reject the null hypothesis and conclude that the population variance is less than or equal to 0.81. O The test is inconclusive because the p-value is nearly 0. One can not make a decision with the p-value alone. We need both a p-value and the value of test statistic to make a conclusion.
A random sample of test scores for an apptitude test is given below. Use a = .05 to perform the goodness of fit test to see whether the data<br>came from a Normal distribution. What is the rejection for this test?<br>55, 86, 94, 58, 55, 95, 55, 52, 69, 95, 90, 65, 87, 50, 56, 55, 57, 98, 58, 79, 92, 62, 59, 88, 65.<br>Reject H if Test Statistic > x? where a is the level of significance and there are k-3 degrees of freedom<br>0.<br>where k is the number of intervals that are used to bin or group data.<br>O Reject H if Test Statistic > where a is the level of significance and there are k-3 degrees of freedom<br>a/2<br>where k is the number of intervals that are used to bin or group data,<br>O Reject H if Test Statistic > x? where a is the level of significance and there are k-1 degrees of freedom<br>where k is the number of intervals that are used to bin or group data.<br>O Reject H if Test Statistic > y where a is the level of significance and there are k-2 degrees of freedom<br>where k is the number of intervals that are used to bin or group data,<br>

Extracted text: A random sample of test scores for an apptitude test is given below. Use a = .05 to perform the goodness of fit test to see whether the data came from a Normal distribution. What is the rejection for this test? 55, 86, 94, 58, 55, 95, 55, 52, 69, 95, 90, 65, 87, 50, 56, 55, 57, 98, 58, 79, 92, 62, 59, 88, 65. Reject H if Test Statistic > x? where a is the level of significance and there are k-3 degrees of freedom 0. where k is the number of intervals that are used to bin or group data. O Reject H if Test Statistic > where a is the level of significance and there are k-3 degrees of freedom a/2 where k is the number of intervals that are used to bin or group data, O Reject H if Test Statistic > x? where a is the level of significance and there are k-1 degrees of freedom where k is the number of intervals that are used to bin or group data. O Reject H if Test Statistic > y where a is the level of significance and there are k-2 degrees of freedom where k is the number of intervals that are used to bin or group data,
Jun 11, 2022
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