A proton (q = 1.6 x 10 -19 C and m p = 1.67 x 10 -27 kg) is accelerated from rest by a potential difference of 350 V. It then enters a uniform magnetic field of magnitude 200 mT with its velocity...


A proton (q = 1.6 x 10-19
C and mp
= 1.67 x 10-27
kg) is accelerated from rest by a potential difference of 350 V. It then enters a uniform magnetic field of magnitude  200  mT  with its velocity  perpendicular to the field . Find:  The speed of the proton, The radius of its path in the magnetic field, The period of the proton and its frequency



Jun 01, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here