A survey conducted by the Pew Foundation found that 536 of 908 Twitter users say they use Twitter for get news. We wish to find a 95% confidence interval for the proportion of Twitter users who use it...


A survey conducted by the Pew Foundation found that 536 of 908 Twitter users say they use Twitter for get news. We wish to find a 95% confidence interval for the proportion of<br>Twitter users who use it to get news.<br>What is the sample statistic?<br>• Use percentiles on a bootstrap distribution to find the 95% confidence interval.<br>• We can model the bootstrap distribution with a normal distribution with mean equal to the sample statistic and standard deviation equal to the<br>standard error of the bootstrap distribution. Give the mean<br>normal distribution to find the 95% confidence interval.<br>and standard deviation for this normal distribution. Use percentiles on this<br>• What is z' for a 95% confidence interval?<br>Use the formula

Extracted text: A survey conducted by the Pew Foundation found that 536 of 908 Twitter users say they use Twitter for get news. We wish to find a 95% confidence interval for the proportion of Twitter users who use it to get news. What is the sample statistic? • Use percentiles on a bootstrap distribution to find the 95% confidence interval. • We can model the bootstrap distribution with a normal distribution with mean equal to the sample statistic and standard deviation equal to the standard error of the bootstrap distribution. Give the mean normal distribution to find the 95% confidence interval. and standard deviation for this normal distribution. Use percentiles on this • What is z' for a 95% confidence interval? Use the formula "Statistic + z· SE" to find the 95% confidence interval. • Compare the three answers. 4. Obesity in America: Exercises vs Non-exercisers Also in Chapter 3, we see that the difference in mean BMI between non-exercisers (those who said they had not exercised at all in the last 30 days) and exercisers (who said they had exercised at least once in the last 30 days) is , with a standard error for the estimate of SE = 0.016. If we use the normal distribution to find a 90% confidence interval for the difference in mean BMI between the two groups: a. What is z*? (b) Find and interpret the 90% confidence interval.

Jun 11, 2022
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