Multiple Regression & ANOVA 1) Using Model 2 from the Coefficients table (Table 1.) below from today’s slides, please complete the following interpretations below for our regression coefficients for...

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Anything in blue should be done completed already. Struggling understanding the rest



Multiple Regression & ANOVA 1) Using Model 2 from the Coefficients table (Table 1.) below from today’s slides, please complete the following interpretations below for our regression coefficients for Sun and Advertising. Rainfall is already completed for you as an example. I have provided you with the actual tables below rather than snapshots of them in order to help you see them more clearly. Rainfall: b = 0.085 Mean Weekly Rainfall contributes significantly to our model (or significantly predicts our outcome variable), t = 12.261, p < .001.="" as="" mean="" weekly="" rainfall="" increases="" by="" one="" unit,="" umbrella="" sale="" numbers="" increase="" by="" 0.085="" units.="" both="" variables="" were="" measured="" in="" hundreds;="" therefore,="" for="" every="" 100="" more="" mm="" of="" rain,="" an="" extra="" 8.5="" umbrellas="" are="" sold.="" ="" sun:="" b="3.367" the="" mean="" weekly="" sun="" also="" contributes="" significantly="" at="" the="" 99%="" confidence="" level="" to="" umbrella="" sales="" with="" the="" p-value="" being="" p="">< .001="" (.000).="" what="" this="" tells="" us="" is="" that="" every="" week="" we="" have="" sunshine="" results="" in="" an="" extra="" 3.367="" umbrellas="" sold="" that="" week.="" advertising:="" b="11.086" the="" mean="" weekly="" advertising="" also="" contributes="" significantly="" at="" the="" 99%="" confidence="" level="" to="" umbrella="" sales="" with="" the="" p-value="" being="" p="">< .001="" (.000).="" what="" this="" tells="" us="" is="" that="" every="" week="" we="" place="" advertisements="" for="" umbrellas,="" the="" corresponding="" sales="" result="" in="" an="" extra="" 11.086="" umbrellas="" sold="" that="" week.="" table="" 1.="" coefficients="" unstandardized="" standardized="" bc="" 95%="" confidence="" interval="" coefficients="" coefficients="" b="" model="" b="" std.="" error="" beta="" t="" sig="" lower="" upper="" 1="" (constant)="" 134.140="" 7.537="" 17.799="" .000="" 119.278="" 149.002="" mean="" weekly="" rainfall="" (hundreds)="" .096="" .010="" .578="" 9.979="" .000="" .077="" .115="" 2="" (constant)="" -26.613="" 17.350="" -1.534="" .127="" -60.830="" 7.604="" mean="" weekly="" rainfall="" (hundreds)="" .085="" .007="" .511="" 12.261="" .000="" .071="" .099="" mean="" weekly="" sun="" 3.367="" .278="" .512="" 12.123="" .000="" 2.820="" 3.915="" mean="" weekly="" advertising="" 11.086="" 2.438="" .192="" 4.548="" .000="" 6.279="" 15.894="" dependent="" variable:="" umbrella="" sales="" (hundreds)="" 2)="" please="" use="" table="" 1.="" above="" again="" to="" complete="" the="" following="" interpretations="" below="" for="" our="" standardized="" regression="" coefficients="" for="" sun="" and="" advertising="" from="" model="" 2="" only.="" rainfall="" is="" already="" completed="" for="" you="" as="" an="" example="" ·="" rainfall:="" standardized="0.511" mean="" weekly="" rainfall="" contributes="" significantly="" to="" our="" model="" (or="" significantly="" predicts="" our="" outcome="" variable),="" t="12.261," p="">< .001.="" as="" average="" weekly="" rainfall="" increases="" by="" one="" standard="" deviation,="" umbrella="" sales="" increase="" by="" 0.511="" standard="" deviations.="" ·="" sun:="" standardized="0.512" mean="" sunshine="" also="" contributes="" significantly="" to="" the="" model="" of="" significantly="" predicting="" the="" outcome="" variable="" p="">< .001="" (.000="" significance).="" per="" one="" standard="" deviation="" of="" increased="" average="" sunshine="" per="" week,="" umbrella="" sales="" increase="" by="" 0.512="" standard="" deviation="" which="" is="" very="" much="" the="" same="" to="" additional="" increased="" weekly="" rainfall="" (0.511).="" ·="" advertising:="" standardized="0.192" similarly,="" mean="" advertising="" also="" contributes="" significantly="" to="" the="" model="" of="" significantly="" predicting="" the="" outcome="" variable="" p="">< .001 (.000 significance). per one standard deviation of increased advertisements per week, umbrella sales increase by 0.192 standard deviation. the contribution of increased advertisement yields less than both the increase rainfall and increased sunshine toward umbrella sales. 3) please respond to the following: a. why is adjusted r2 always smaller than r2? the adjusted r2 number is adjusted down from for the r2 number by subtracting the number of predictors in the model. b. the table below (table 2.) uses wherry’s formula to calculate adjusted r2. there issue with this because it is not provide a robust measure of adjusted r2. please use stein’s formula to calculate adjusted r2 from the r2 in the table below. stein’s formula: 1−[(?−1)(?−?−1)(?−2)(?−?−2)(?+1)?](1−?2) table 2. model summary model r r square adjusted r square std. error of est. r square change f change df 1 df 2 sig. f change 1 .578 .335 .331 65.991 .335 99.587 1 198 .000 2 .815 .665 .660 47.087 .330 96.447 2 196 .000 model 1 predictors: (constant), mean weekly rainfall (hundreds) model 2 predictors: (constant), mean weekly rainfall (hundreds), mean weekly sun, mean weekly advertising dependent variable: umbrella sales (hundreds) 4) please respond to the following questions regarding ssm and ssr: a. as discussed in class this week, in the anova situation, the ssm requires us to calculate the differences between each participant’s predicted value and the grand mean. what is each participant’s predicted value in anova? b. in the anova situation, ssm includes calculating the differences between what the model predicts and the grand mean. whereas ssr includes calculating the differences between what the model predicts and __________________ c. consider an independent anova situation with one iv that has three groups. let’s assume n=60 and participants are randomly assigned to each of the three groups with 20 individuals in each group. let’s assume the mean of the base group is 12.25, the mean of the low dose group is 14.28 and the mean of the high dose group is 17.43. let’s also assume that the grand mean is 15.36. please calculate the ssm for the anova situation. please make sure to show your work. d. in an anova situation, if our sst is 53.78 and our ssm is 34.12. what is the value of ssr. please show your work. 5) please respond to the following: a. using the regression equation to model an independent anova, the intercept (b0) is equal to what? b. using the regression equation to model an independent anova with 4-groups, the value of b1 is equal to what? .001="" (.000="" significance).="" per="" one="" standard="" deviation="" of="" increased="" advertisements="" per="" week,="" umbrella="" sales="" increase="" by="" 0.192="" standard="" deviation.="" the="" contribution="" of="" increased="" advertisement="" yields="" less="" than="" both="" the="" increase="" rainfall="" and="" increased="" sunshine="" toward="" umbrella="" sales.="" 3)="" please="" respond="" to="" the="" following:="" a.="" why="" is="" adjusted="" r2="" always="" smaller="" than="" r2?="" the="" adjusted="" r2="" number="" is="" adjusted="" down="" from="" for="" the="" r2="" number="" by="" subtracting="" the="" number="" of="" predictors="" in="" the="" model.="" b.="" the="" table="" below="" (table="" 2.)="" uses="" wherry’s="" formula="" to="" calculate="" adjusted="" r2.="" there="" issue="" with="" this="" because="" it="" is="" not="" provide="" a="" robust="" measure="" of="" adjusted="" r2.="" please="" use="" stein’s="" formula="" to="" calculate="" adjusted="" r2="" from="" the="" r2="" in="" the="" table="" below.="" stein’s="" formula:="" 1−[(?−1)(?−?−1)(?−2)(?−?−2)(?+1)?](1−?2)="" table="" 2.="" model="" summary="" model="" r="" r="" square="" adjusted="" r="" square="" std.="" error="" of="" est.="" r="" square="" change="" f="" change="" df="" 1="" df="" 2="" sig.="" f="" change="" 1="" .578="" .335="" .331="" 65.991="" .335="" 99.587="" 1="" 198="" .000="" 2="" .815="" .665="" .660="" 47.087="" .330="" 96.447="" 2="" 196="" .000="" model="" 1="" predictors:="" (constant),="" mean="" weekly="" rainfall="" (hundreds)="" model="" 2="" predictors:="" (constant),="" mean="" weekly="" rainfall="" (hundreds),="" mean="" weekly="" sun,="" mean="" weekly="" advertising="" dependent="" variable:="" umbrella="" sales="" (hundreds)="" 4)="" please="" respond="" to="" the="" following="" questions="" regarding="" ssm="" and="" ssr:="" a.="" as="" discussed="" in="" class="" this="" week,="" in="" the="" anova="" situation,="" the="" ssm="" requires="" us="" to="" calculate="" the="" differences="" between="" each="" participant’s="" predicted="" value="" and="" the="" grand="" mean.="" what="" is="" each="" participant’s="" predicted="" value="" in="" anova?="" b.="" in="" the="" anova="" situation,="" ssm="" includes="" calculating="" the="" differences="" between="" what="" the="" model="" predicts="" and="" the="" grand="" mean.="" whereas="" ssr="" includes="" calculating="" the="" differences="" between="" what="" the="" model="" predicts="" and="" __________________="" c.="" consider="" an="" independent="" anova="" situation="" with="" one="" iv="" that="" has="" three="" groups.="" let’s="" assume="" n="60" and="" participants="" are="" randomly="" assigned="" to="" each="" of="" the="" three="" groups="" with="" 20="" individuals="" in="" each="" group.="" let’s="" assume="" the="" mean="" of="" the="" base="" group="" is="" 12.25,="" the="" mean="" of="" the="" low="" dose="" group="" is="" 14.28="" and="" the="" mean="" of="" the="" high="" dose="" group="" is="" 17.43.="" let’s="" also="" assume="" that="" the="" grand="" mean="" is="" 15.36.="" please="" calculate="" the="" ssm="" for="" the="" anova="" situation.="" please="" make="" sure="" to="" show="" your="" work.="" d.="" in="" an="" anova="" situation,="" if="" our="" sst="" is="" 53.78="" and="" our="" ssm="" is="" 34.12.="" what="" is="" the="" value="" of="" ssr.="" please="" show="" your="" work.="" 5)="" please="" respond="" to="" the="" following:="" a.="" using="" the="" regression="" equation="" to="" model="" an="" independent="" anova,="" the="" intercept="" (b0)="" is="" equal="" to="" what?="" b.="" using="" the="" regression="" equation="" to="" model="" an="" independent="" anova="" with="" 4-groups,="" the="" value="" of="" b1="" is="" equal="" to="">
Answered Same DayOct 05, 2021

Answer To: Multiple Regression & ANOVA 1) Using Model 2 from the Coefficients table (Table 1.) below from...

Rajeswari answered on Oct 06 2021
132 Votes
Multiple Regression & ANOVA
Using Model 2 from the Coefficients table (Table 1.) below from today’s slides, please complete the following interpretations below for our regression coefficients for Sun and Advertising. Rainfall is already completed for you as an e
xample. I have provided you with the actual tables below rather than snapshots of them in order to help you see them more clearly.
Rainfall: b = 0.085
Mean Weekly Rainfall contributes significantly to our model (or significantly predicts our outcome variable), t = 12.261, p < .001. As mean weekly rainfall increases by one unit, umbrella sale numbers increase by 0.085 units. Both variables were measured in hundreds; therefore, for every 100 more mm of rain, an extra 8.5 umbrellas are sold. 
Sun: b = 3.367
The hypothesis testing for slope =0 vs slope not equal to 0 gives the test statistic 12.123 and p value <0.001.
This implies our null hypothesis is false.
The mean weekly sun also contributes significantly at the 99% confidence level to umbrella sales.
The slope is significant and hence we can expect for 1 unit rise of mean Sun in a week, we can have 3.367
umbrellas extra sold that week.
    Similarly for 1 unit fall in mean Sun we expect umbrella sales to fall by 3.367 units. i.e. 3.367 is the rate of change of sales of umbrella with respect to mean Sun weekly
Advertising: b = 11.086
The mean weekly advertising also contributes significantly at the 99% confidence level to umbrella sales. This is because for hypothesis testing for slope =0 vs slope not equal to 0 we got test statistic as 4.548 with the p-value being p < .001 (.000). Hence slope is significant and since slope is positive 4.548, this gives the rate of change of umbrella sales for change in advertising.
What this tells us is that every week we place advertisements for umbrellas, the corresponding sales result in an extra 11.086 umbrellas sold that week. i.e. for 1 advertisement extra we can have 11.086 umbrellas more sold.
Table 1.
Coefficients
                 Unstandardized Standardized BC 95% Confidence Interval    
Coefficients Coefficients B
    Model
    B
    Std. Error
    Beta
    t
    Sig
    Lower
    Upper
    1 (Constant)
    134.140
    7.537
    
    17.799
    .000
    119.278
    149.002
     Mean Weekly Rainfall (hundreds)
    .096
    .010
    .578
    9.979
    .000
    .077
    .115
    2 (Constant)
    -26.613
    17.350
    
    -1.534
    .127
    -60.830
    7.604
     Mean Weekly Rainfall (hundreds)
    .085
    .007
    .511
    12.261
    .000
    .071
    .099
     Mean Weekly...
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