Attached file problems

81119 assignment
1.
The aperture stop (AS) is the stop or lens ring, which physically limits the solid angle of rays passing through the system from an on-axis object point. The aperture stop limits the brightness of an image
Here hence a) the lens is the aperture stop, the entrance pupil and the exit pupil coincides with the lens.
b) Field stop is nothing but the diaphragm, The entrance port is 100/3 = 33.33 mm to the right of lens.
c) Angular real and apparent view would be equal to arcsin (20/25) = 53.1 degrees. Linear field of view is 50 mm.
a) Lens no 1 would be the aperture top here, the entrance pupil coincides with this. The exit pupil is
Consider the right triangle with half angle of cone of light collected by lens.
So sin theta = 0.5/1 = 0.5 hence theta = 30 deg.
Diameter of entrance pupil = 100 mm focal length *f/8 divided by f = 100/8 = 12.5 mm
f/16 camera lens expose the film at time 1 second
Hence f/4 camera .. ?
We know inversely proportional to square
i.e. Answer is 1 sec *f^2/256 divided by f^2/16 = 1/16 = 0.0625 seconds
Qno.13
The optical tube length (OTL) is defined as the distance between the back focal point of the objective and the front focal point of the eyepiece. The optical tube length has been standardized to be 160 mm
Magnification = OTL/f = 160/16 = 10 time
a) NA of lens = N sin t = 1.513 *0.075 = 0.1136
b) Resolvable separation of two points on slide = 0.00298 mm
c) this is the minimum distance at which two distinct points of a specimen can still be seen - either by the observer or the microscope camera - as separate...