btandard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed 0.3+ O Two-tailed Step 2: Enter the critical value(s). (Round to 3 decimal places.) 02- 01- Step 3: Enter the test...


btandard Normal Distribution<br>04<br>Step 1: Select one-tailed or two-tailed.<br>O One-tailed<br>0.3+<br>O Two-tailed<br>Step 2: Enter the critical value(s).<br>(Round to 3 decimal places.)<br>02-<br>01-<br>Step 3: Enter the test statistic.<br>(Round to 3 decimal places.)<br>21<br>(c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management.<br>Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence<br>

Extracted text: btandard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed 0.3+ O Two-tailed Step 2: Enter the critical value(s). (Round to 3 decimal places.) 02- 01- Step 3: Enter the test statistic. (Round to 3 decimal places.) 21 (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence
E=<br>Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management<br>claims the mean customer rating, u, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 76.2. Assume that the<br>population standard deviation of customer ratings is 22.8.<br>Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of<br>significance.<br>(a) State the null hypothesis H, and the alternative hypothesis H,.<br>Ho<br>Aa<br>O<O<br>H: ]<br>D=D<br>(b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a

Extracted text: E= Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 76.2. Assume that the population standard deviation of customer ratings is 22.8. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H,. Ho Aa O

Jun 11, 2022
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