c Other I imag equations c a an be found which relte the o )ject and e posit uni r their distances from. the center of curvature or from the principal tocit relation). Exercises 3.1 Light strikes the...

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Other I imag equations c a an be found which relte the o )ject and e posit uni r their distances from. the center of curvature or from the principal tocit relation).
Exercises
3.1 Light strikes the spherical surface of a lens at an angle of incidence of 25'. Calculate Li angle of refraction if the glass has a refractive index of 1.5. 3.2 The radius of the circle containing the three fixed legs of a spherometer is 25 mm. T instrument is placed on a convex spherical surface of curvature 3 D. By how much vi the central leg have to be raised above the outer legs to be just in contact with the surfed( An optician's lens measure has its outer points 18 mm apart, and a depression of I center point of 0.8 mm gives a reading of +9.25 D on its scale. For what refract index was it scaled? A lens measure applied to a brass tube of 230 mm external diameter gave a reading 4.75 D. For what refractive index was it adjusted? 3.5 3.6 For distant nhk;a following distance Calculate the reduced vergences at the refracting surface for object points located at u 4 e surface (assume n =7 1): (a) sa250 mny, (b) +40 cm wed °fore refraction at a surl
3.4
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from. the center of curvature or from the principal tocit relation).
Exercises
3.1 Light strikes the spherical surface of a lens at an angle of incidence of 25'. Calculate Li angle of refraction if the glass has a refractive index of 1.5. 3.2 The radius of the circle containing the three fixed legs of a spherometer is 25 mm. T instrument is placed on a convex spherical surface of curvature 3 D. By how much vi the central leg have to be raised above the outer legs to be just in contact with the surfed( An optician's lens measure has its outer points 18 mm apart, and a depression of I center point of 0.8 mm gives a reading of +9.25 D on its scale. For what refract index was it scaled? A lens measure applied to a brass tube of 230 mm external diameter gave a reading 4.75 D. For what refractive index was it adjusted? 3.5 3.6 For distant nhk;a following distance Calculate the reduced vergences at the refracting surface for object points located at u 4 e surface (assume n =7 1): (a) sa250 mny, (b) +40 cm wed °fore refraction at a surl
3.4
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Answered Same DayDec 22, 2021

Answer To: c Other I imag equations c a an be found which relte the o )ject and e posit uni r their distances...

David answered on Dec 22 2021
105 Votes
Solution
Radius of curvature = 50mm
n = 1.53
Distance of Object (u) = 30mm
Since the light i
s coming from denser to Rarer so from Refraction formula
1/v – n/u = (n-1)/ R
1/v = (n-1)/R + n/u
1/v = .53/50 – 1.53 / 30
On calculation we get
v = -24.75cm = - 24.8cm ( Answer)
for magnification we have
m = nv/u
m = 1.26 ( Answer)
Solution
n' = 4/3
v = +25cm
u = -160mm = -16cm
so from the given...
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