C programming please use macOS ONLY on terminal There is 7 question You can see the Exercises in here The figure will be in the link...

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C programming please use macOS ONLY on terminal



There is 7 question You can see the

Exercises in here The figure will be in the link




https://www.masterraghu.com/subjects/np/introduction/unix_network_programming_v1.3/ch02lev1sec15.html



If code please do a screenshot and well explain



Text question



1. We have mentioned IP versions 4 and 6. What happened to version 5 and what were



versions 0, 1, 2, and 3? (Hint: Find the IANA's "Internet Protocol" registry.



2 . Where would you look to find more information about the protocol that is assigned IP



version 5?



3 . With Figure 2.5, we said that TCP assumes an MSS of 536 if it does not receive an MSS



option from the peer. Why is this value used?



4 . Draw a figure like Figure 2.5 for the daytime client/server in Chapter 1, assuming the server



returns the 26 bytes of data in a single TCP segment.



5. A connection is established between a host on an Ethernet, whose TCP advertises an MSS



of 1,460, and a host on a Token Ring, whose TCP advertises an MSS of 4,096. Neither host



implements path MTU discovery. Watching the packets, we never see more than 1,460



bytes of data in either direction. Why?



6 . In Figure 2.19, we said that OSPF uses IP directly. What is the value of the protocol field



in the IPv4 header (Figure A.1) for these OSPF datagrams?



7 . In discussing SCTP output, we said that the SCTP sender must wait for the cumulative



acknowledgment point to pass sent data before the data could be freed from the socket



buffer. If a selective acknowledgment shows that data is acknowledged beyond the



cumulative acknowledgment point, why can't the data be freed?

Answered 1 days AfterSep 14, 2022

Answer To: C programming please use macOS ONLY on terminal There is 7 question You can see the Exercises in...

Samdish answered on Sep 16 2022
59 Votes
Answer 2.1:
As per designers of Internet Protocol, IPv1 and IPv2 were violating principle of layeri
ng approach. At that point of time TCP was designed to work on both host-to-host and internet packing/routing protocol. Which was later separated in IPv3.
IPv1, v2 and v3 were created but were not released. Reason for that was, they were not stable. Therefore, IPv4 was made with corrections.
IPv5 was experimental real time streaming protocol. It was also based on 32-bit and used same addressing system as IPv4. So, it was not accepted as official...
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