Calculate the Pcoz given. Cas(POa)z 2 3 Ca"+ 2PO- log k=-327 pH= 8, PO 10 M T=25°C TH 10 M • Varlables needed for solution of carbonate equlibrlum • For all systems mentioned, there Is a maximum of 7...

Calculate the Pcoz given. Cas(POa)z 2 3 Ca"+ 2PO- log k=-327 pH= 8, PO 10 M T=25°C TH 10 M • Varlables needed for solution of carbonate equlibrlum • For all systems mentioned, there Is a maximum of 7 variables, at dT = 0 and dP = 0 aco2 = Pco2i aH2C03; aHCO3-; ac03-2; aHoi aOH-i aca+2 Note: activity = [x] %3! %3D [Ca+2][CO,2] / [CaCO,] = KCaco3 = 10-8.3 [H*][HCO,]/[H,Cco,] = KH2C03 = 10-6.4 %3D %3! [H*][CO,] / [HCo,] = KHC03. = 10-10.3 %3D [H+][OH] / [H,O] = KH20 = 10-14 %3D [H,CO] / Pco2 = Kcoz = 10-1.47 %3D %3D CALCIUM CARBONATE: SOLUBILITY CALCULATIONS - 5 Solubility of CaCO, CaCo, Ca 2 + CO, 2 From Table A1.2: 9 Lecture 19 Nov i pptx ATtae.