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Chemistry 121 Ch 6 Activity SheetName___________________________ 1. (5 points) Draw the energy diagram for the following reaction. Specify Activation Energy (Ea), Heat of Reaction H, label the axes, and specific reactant and product species on your graph. 2NO(g)↔ N2(g) + O2(g) H = - 43 kcal, Ea = 5 kcal 2. (5 points) A. Write the equilibrium expression for the reaction: 2NO(g) ↔ N2(g) + O2(g B. Calculate the equilibrium constant, at equilibrium concentrations of [N2] = 0.78M, [O2] = 0.21M, [NO]= 9x10-4M. Which does the reaction favor, products or reactants? 3. (5 points) Consider the reaction above at equilibrium in a closed container. Which way would the reaction go (to form more reactants or products) to regain equilibrium under the following conditions, and will the other products and reactants increase or decrease in concentration? Reaction DirectionEffect on reactant(s), product a. More N2 is addedNOO2 b. More NO is addedN2O2 c. The temperature is raised NON2O2 d. O2 is removedNON2 e. Pressure is increased (Vol. decreased)NON2O2 4. (5 points) For the Bunsen burner reaction, CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) H = - 819.5 kJ How much energy (in kJ) is associated with the reaction of burning 5.00 g of CH4 with 9.00 g O2? (Hint: this is a limiting reactant problem)
Answered Same DayMay 16, 2022

Answer To: I attach the file

Dr Shweta answered on May 16 2022
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Chemistry 121 Ch 6 Activity Sheet                Name___________________________
Solutions
1. (5 points) Draw
the energy diagram for the following reaction. Specify Activation Energy (Ea), Heat of Reaction H, label the axes, and specific reactant and product species on your graph.
2NO(g)↔ N2(g) + O2(g)     H = - 43 kcal, Ea = 5 kcal
Ans: Energy diagram for the following reaction is
2. (5 points) A. Write the equilibrium expression for the reaction: 2NO(g) ↔ N2(g) + O2(g
Ans: Kc = [N2] [O2]/[NO]2
B. Calculate the equilibrium constant, at equilibrium concentrations of [N2] = 0.78M,
[O2] = 0.21M, [NO]= 9x10-4M. Which does the reaction favor, products or reactants?
Ans: Kc = 0.78*0.21/ [9*10-4]2
On solving we get, Kc = 2 * 105
Since Kc is greater than 1 so product formation is...
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