d) Z = 2.62 is the test-statistic for this hypothesis test. Use it to find the p-value. (Give the p-value to four decimal places) Will #. be rejected? (Include the numbers for your decision) ) Write a...


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d) Z = 2.62 is the test-statistic for this hypothesis test.<br>Use it to find the p-value.<br>(Give the p-value to four decimal places)<br>Will #. be rejected? (Include the numbers for your<br>decision)<br>) Write a conclusion in context. (This is the answer to<br>the hypothesis test. Make sure it includes context.)<br>g) Which type of error can the statistician have made in<br>the correct conclusion of this hypothesis test? (This is<br>not an error that can be avoided.)<br>h) Can we state the probability with which this error will<br>occur? If so, state the value.<br>

Extracted text: d) Z = 2.62 is the test-statistic for this hypothesis test. Use it to find the p-value. (Give the p-value to four decimal places) Will #. be rejected? (Include the numbers for your decision) ) Write a conclusion in context. (This is the answer to the hypothesis test. Make sure it includes context.) g) Which type of error can the statistician have made in the correct conclusion of this hypothesis test? (This is not an error that can be avoided.) h) Can we state the probability with which this error will occur? If so, state the value.
In the following two hypothesis test problems, the test<br>statistic (z-score) will be given. Following these is a<br>separate problem for which you will have to calculate<br>the z-score using the appropriate formula.<br>1. Swimming at local beaches is affected by the number of<br>bacteria in the water. Bacteria numbers are monitored by<br>taking water samples. In the summer, the mean number<br>of E.Coli bacteria in a water sample at local beaches has<br>usually been 97. The standard deviation is known to be<br>15. If this August 62 water samples from beaches<br>around Annapolis were analyzed and the mean number<br>of E. Coli bacteria found to be 102, does this mean that<br>summertime E. Coli bacteria levels have increased? Use<br>a significance level of 1% for this test. (Note: In part (d),<br>the test statistic (z-score) is GIVEN.)<br>a)<br>102<br>97<br>o =<br>15<br>n =<br>62<br>a =<br>0.01<br>b) Why is a hypothesis test based on the normal<br>distribution justified? (Explain. Don't be too brief<br>and use appropriate terminology.)<br>known therefore, the given<br>hypothesis test is based on normal distribution.<br>The standard deviation<br>c) State the hypotheses in symbols:<br>: H=102<br>: 102 "/>
Extracted text: In the following two hypothesis test problems, the test statistic (z-score) will be given. Following these is a separate problem for which you will have to calculate the z-score using the appropriate formula. 1. Swimming at local beaches is affected by the number of bacteria in the water. Bacteria numbers are monitored by taking water samples. In the summer, the mean number of E.Coli bacteria in a water sample at local beaches has usually been 97. The standard deviation is known to be 15. If this August 62 water samples from beaches around Annapolis were analyzed and the mean number of E. Coli bacteria found to be 102, does this mean that summertime E. Coli bacteria levels have increased? Use a significance level of 1% for this test. (Note: In part (d), the test statistic (z-score) is GIVEN.) a) 102 97 o = 15 n = 62 a = 0.01 b) Why is a hypothesis test based on the normal distribution justified? (Explain. Don't be too brief and use appropriate terminology.) known therefore, the given hypothesis test is based on normal distribution. The standard deviation c) State the hypotheses in symbols: : H=102 : ">102
Jun 11, 2022
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