Due date: 11:45pm AEST, Friday, Week 10 Weighting: 30% ObjectivesThis assessment task requires you to demonstrate your knowledge of routing concepts by completing a number of exercises. You will...

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Due date: 11:45pm AEST, Friday, Week 10 Weighting: 30% ObjectivesThis assessment task requires you to demonstrate your knowledge of routing concepts by completing a number of exercises. You will utilize material learned in the unit and also extend that learning through additional reading where appropriate.The assignment is designed to help you to achieve the unit learning outcomes as listed in the unit profile.InstructionsYou must do this assignment on your own – it is not a group assignment.Type all your answers in the separate ‘Answer Template Assignment TWO’ doc that you can download from the unit website, and submit only the completed template. Answers that are not typed into the Answer Template may not be marked or may be returned to you for retyping and re-submission and late penalties will apply.You can download the Answer Template Assignment TWO doc from the Written Assignment 2 link found in the Assessment menu in Moodle.Where instructed, you must show the steps you took to arrive at your answers. Write your answers in your own words to avoid potential plagiarism and copyright violations.You must submit the Answer Template Assignment TWO in its original Word file (.doc or .docx) format. Do not submit any other type of file.Plagiarism Procedures can be found in the CQUniversity Policies section of the Unit Profile.Assessment Requirements and Marking CriteriaThere are 3 main questions with sub-questions and the requirements are stated for each one. You must answer all questions and sub-questions if any. Marks are indicated and also shown in the Answer Template.Marking criteria: Your answers will be marked based on technical correctness, completeness, clarity and relevance. Questions that ask you to show your working or calculations or the steps you took to arrive at your answers, may have marks deducted if such information is not provided. The Assignment questions begin on the next page.REMEMBER, USE THE PROVIDED ANSWER TEMPLATE FOR ALL YOURANSWERS. THE ANSWER TEMPLATE IS AVAILABLE FROM THE WEBSITE Question 1 – Routing Table construction (10 marks)Refer to Fig.1, assume that all the networks shown are aware of each other and have fully updated routing tables and R4 was configured as default router. Construct the routing table for routers R1 and R3. List masks in longest mask order, and in dotted-decimal format.Fig. 1 Network DiagramQuestion 2 – Forwarding process – classless addressing (8 marks)First understand the forwarding process as explained in Forouzan Chapter 6, Section 6.2. Answer the following questions.a)Refer to Figure 1 network diagram from question 1. Assume that a packet arrives at R3 with a destination address of 220.10.41.120. Show the router’s forwarding process, that is, all the calculations it does to determine where to send the packet, the results at each step, and explain the router’s decision at the end. Use a table to organize your data (3 marks).b)In the same diagram (Figure 1), assume that another packet arrives at R3 with a destination address of 161.22.3.10. Show the router’s forwarding process, that is, allthe calculations it does to determine where to send the packet, the results at each step, and explain the routers decision at the end. Use a table to organize your data (3 marks).c)Tables for a) and b) are clear and shows all relevant data, and calculations shown are sound (2 marks).Question 3 – Wireless Networking (7 marks)Consider the following scenario: To promote their “learning for everyone” campaign, the city council has organised a 2-week pop-up “uni-campus” to be located within the grounds of a large inner city 30-acre park. The uni-campus will host up to 40 different courses that members of the public can enrol into. On offer so far are: a 4-day course in commercial art; a 3-day course in basic Microsoft office; a 1-day course in how to cut your own hair; a 4-day course in high school math; a 2-day course in basic Internet; a 2-day workshop in creating a foolproof CV; a 3-day ‘lets do it now’ course in creative writing and many more. The courses will all be run from different stalls conducted by respective teaching staff at each stall. Courses cost from $15 – 45 depending on the course. An online assessment and certificate are available on conclusion of learning. Chairs will be provided to accommodate up to 15 students each session per course. The popup campus will include a latest-model office-quality printer to be accessible only to uni-campus patrons. An RJ-45 connection to a council network switch is available from a secure cabinet located in the park near the unicampus site. Power is available at each stall.The council has decided that all patrons and park visitors should have free but secure wireless access to the Internet while they are in the park so they can connect to various webpages relevant to the event and participate in the online activities. You have been given the task of setting up a wireless network to serve this need for the duration of the pop-up campus. Three types of wireless LANs are the Independent Basic Service Set (IBSS), the Extended Service Set (ESS) and the Mesh Wireless network. Briefly explain each of these wireless architectures in your own words, the pros and cons of each type, an evaluation of its suitability for your network, and how you would set each one up in the park. Finally nominate the type that you would implement and give clear reasons for your selection.Hints: First, research or review each of the types of wireless LANs. Next, study the given scenario thoroughly – your solution must cater for all stated requirements, be technically sound, take the context into account, and any assumptions made should be reasonable and stated. Finally, write up your answer, using your own words.Remember that quotations alone will not be accepted as an explanation. Quotations can support your explanations, but you must still provide the main explanation yourself. Best way forward is to keep direct quotations to a minimum and use your own words. Remember we are looking for your personal ability to understand and apply principles you have learned. Question 4 -- Fragmentation (5 marks) An IP datagram 5,400 bytes long with no options arrives at a router, which determines that the next destination is an Ethernet network through which the datagram must travel. Answer the following questions, showing your calculations and reasoning. a)Assume that the router decides to fragment the packet into 4 fragments. Determine a correct size for each fragment and identify the starting byte and ending byte of each fragment (2.5 marks).b)Calculate the fragmentation offset for each fragment (1.5 marks).c)The total number of bytes from all 4 fragments leaving the router will be greater than the initial datagram size that arrived. Explain by how much, and the reason for this.(1 mark).End of assignment two
Answered Same DaySep 12, 2021

Answer To: Due date: 11:45pm AEST, Friday, Week 10 Weighting: 30% ObjectivesThis assessment task requires you...

Riya answered on Sep 14 2021
132 Votes
1.
R3 routing table:
    Mask
    Network Address
    Next Hop Address
    Interface
    /24
    220.10.40.0
    -----------
    m0
    /22
    140.21.0.0
    -----------
    m1
    /21
    161.22.0.0
    220.10.40.4
    m0
    /20
    200.11.48.0
    220.10.40.2
    m0
    /18
    150.32.0.0
    220.10.40.2
    m0
    Any
    Any
    220.10.40.3
    m0
R1 routing table:
    Mask
    Network Address
    Next Hop Address
    Interf
ace
    /24
    220.10.40.0
    -----------
    m0
    /22
    140.21.0.0
    220.10.40.1
    m0
    /21
    161.22.0.0
    -----------
    m1
    /20
    200.11.48.0
    220.10.40.2
    m0
    /18
    150.32.0.0
    220.10.40.2
    m0
    Any
    Any
    220.10.40.3
    m0
2.
a.)Refer to the routing table of R3 shown in question 1.
Packet with destination address 220.10.41.120
For mask /24:
We perform and operation between binary equivalent of 220.10.41.120 and 11111111.11111111.11111111.00000000
Binary equivalent of 220.10.41.120 is :
11011100.00001010.00101001.01111000
Perform AND operation:
11011100.00001010.00101001.01111000
11111111.11111111.11111111.00000000
11011100.00001010.00101001.00000000
The result is 220.10.41.0 which does not match the corresponding network address
For mask /22:
We perform and operation between binary equivalent of 220.10.41.120 and 11111111.11111111.11111100.00000000
Binary equivalent of 220.10.41.120 is :
11011100.00001010.00101001.01111000
Perform AND operation:
11011100.00001010.00101001.01111000
11111111.11111111.11111100.00000000
11011100.00001010.00101000.00000000
The result is 220.10.40.0 which does not match the corresponding network address
For mask /21:
We perform and operation between binary equivalent of 220.10.41.120 and 11111111.11111111.11111000.00000000
Binary equivalent of 220.10.41.120 is :
11011100.00001010.00101001.01111000
Perform AND operation:
11011100.00001010.00101001.01111000
11111111.11111111.11111000.00000000
11011100.00001010.00101000.00000000
The result is 220.10.40.0 which does not match the corresponding network address
For mask /20:
We perform and operation between binary equivalent of 220.10.41.120 and 11111111.11111111.11110000.00000000
Binary equivalent of 220.10.41.120 is :
11011100.00001010.00101001.01111000
Perform AND operation:
11011100.00001010.00101001.01111000
11111111.11111111.11110000.00000000
11011100.00001010.00100000.00000000
The result is 220.10.32.0 which does not match the corresponding network address
For mask /18:
We perform and operation between binary equivalent of 220.10.41.120 and 11111111.11111111.11000000.00000000
Binary equivalent of 220.10.41.120 is :
11011100.00001010.00101001.01111000
Perform AND operation:
11011100.00001010.00101001.01111000
11111111.11111111.11000000.00000000
11011100.00001010.00000000.00000000
The result is 220.10.0.0 which does not match the corresponding network address
    Mask
    Network Address
    Result
    Remarks
    /24
    220.10.40.0
    220.10.41.0
    Does not match
    /22
    140.21.0.0
    220.`10.40.0
    Does not match
    /21
    161.22.0.0
    220.10.40.0
    Does not match
    /20
    200.11.48.0
    220.10.32.0
    Does not match
    /18
    150.32.0.0
    220.10.0.0
    Does not match
None of the masks applied to the destination address match with the corresponding network address. When it reaches the end of the table the module gives the next hop address 220.10.40.3 and interface number m0 to ARP .This is probably an outgoing package that needs to be sent via the default router .
b.)Refer to the routing table of R3 shown in question 1.
Packet with destination address 161.22.3.10
For mask /24:
We perform and operation between binary equivalent of 161.22.3.10 and 11111111.11111111.11111111.00000000
Binary equivalent of 161.22.3.10 is :
10100001.00010110.00000011.00001010
Perform...
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