f) To determine the predicted purchase amt for a cUstomer who has spent 30 minutes the website ? the results The regression equation bafed ニ -3.53+7,12x ic purcha s -3.53+1.12 time Substitute time =30...

Data were collected to explain the amount of a customer’s purchase (expressed in $’s) based on the amount of time the customer has spent on the company’s website (expressed in minutes) *COMPLETE THE DATA TABLE BELOW*f) To determine the predicted purchase amt for<br>a cUstomer who has spent<br>30 minutes<br>the website ?<br>the<br>results<br>The regression equation bafed<br>ニ -3.53+7,12x<br>ic purcha s<br>-3.53+1.12 time<br>Substitute time =30 in<br>the equation<br>Purchase =<br>-3.53+7.12 time<br>-3. 53+7,1230=~3,53+213,63<br>ニ<br>$210,07<br>

Extracted text: f) To determine the predicted purchase amt for a cUstomer who has spent 30 minutes the website ? the results The regression equation bafed ニ -3.53+7,12x ic purcha s -3.53+1.12 time Substitute time =30 in the equation Purchase = -3.53+7.12 time -3. 53+7,1230=~3,53+213,63 ニ $210,07
3) Data were collected to explain the amount of a customer's purchase (expressed in $'s) based on the<br>amount of time the customer has spent on the company's website (expressed in minutes)<br>Complete the Table Below<br>Regression<br>Statistics<br>Multiple R<br>R Square<br>Adjusted R Square<br>Standard Error<br>0,508<br>Observations<br>12<br>ANOVA<br>Significance F<br>0.005598142<br>df<br>MS<br>F<br>63067.3<br>Regression<br>Residual<br>51086.4<br>Total<br>Standard<br>Error<br>Upper<br>95%<br>Coefficients<br>t Stat<br>P-value<br>Lower 95%<br>Intercept<br>-3.53<br>42.21<br>0.935<br>Time<br>7.12<br>2.03<br>0.006<br>Based on the regression results, answer the following questions<br>a) What is the estimated regression equation?<br>Intercept : -3,53<br>cst<br>reg equi<br>time = 7, 12<br>b) What percentage of the variation in purchase amount is explained by time?<br>STOpel here its time)<br>Y = -3,53+7,12X<br>Adjusted rquare<br>= 0.508<br>0,50X 100 '/<br>5o, 87,<br>c) What is the correlation between purchase amount and time?<br>R -Squared (R2) = 6.S0g<br>correlation (r) r=r=<br>correlatioa btwn purch<br>amount and<br>time<br>0.4127<br>r = 0, SG8<br>r =0. 17<br>d) What is the standard error of the error term in the regression equatiðn?'<br>SE =SSResidual<br>de - SI086,412-2=5108.64 =71,475<br>e) Is the coefficient on the variable “time

Extracted text: 3) Data were collected to explain the amount of a customer's purchase (expressed in $'s) based on the amount of time the customer has spent on the company's website (expressed in minutes) Complete the Table Below Regression Statistics Multiple R R Square Adjusted R Square Standard Error 0,508 Observations 12 ANOVA Significance F 0.005598142 df MS F 63067.3 Regression Residual 51086.4 Total Standard Error Upper 95% Coefficients t Stat P-value Lower 95% Intercept -3.53 42.21 0.935 Time 7.12 2.03 0.006 Based on the regression results, answer the following questions a) What is the estimated regression equation? Intercept : -3,53 cst reg equi time = 7, 12 b) What percentage of the variation in purchase amount is explained by time? STOpel here its time) Y = -3,53+7,12X Adjusted rquare = 0.508 0,50X 100 '/ 5o, 87, c) What is the correlation between purchase amount and time? R -Squared (R2) = 6.S0g correlation (r) r=r= correlatioa btwn purch amount and time 0.4127 r = 0, SG8 r =0. 17 d) What is the standard error of the error term in the regression equatiðn?' SE =SSResidual de - SI086,412-2=5108.64 =71,475 e) Is the coefficient on the variable “time" statistically significantly different than 0 at the 5% level of significance? How do you know? yes, the variable time ,s Sig dif from ø at S Co rres d= 0.05 Ievel because the R-value is less than Sig level f) What is the predicted purchase amount for a customer who has spent 30 minutes on the website? ing Sig is 0,.00c, which.. to time 5
Jun 11, 2022
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