Need help figuring out these equations and problems, I need a guide to solve one so I can figure out the rest. fraction remaining after a second extraction will be given by: VB Fx ((Px,ABVA+VB) (4)...


Need help figuring out these equations and problems, I need a guide to solve one so I can figure out the rest.


fraction remaining after a second extraction will be given by:<br>VB<br>Fx<br>((Px,ABVA+VB)<br>(4)<br>For n extractions, this can be generalized to:<br>VB<br>Fx<br>((Px,ABVA+VB))<br>(5)<br>Since Fx < 1 by definition, the efficiency should increase as the number of extractions increase.<br>An interesting point to note about extraction efficiency can be illustrated in the following<br>problem:<br>Compound X is dissolved in 100 mL of solvent B, and extracted using solvent A. The partition<br>coefficient PXAB has a value of 5.00. What percentage of X remains in solvent B after:<br>A single extraction of 100 mL solvent A<br>Two extractions of 50 mL solvent A<br>five extractions of 20 mL solvent A<br>ten extractions of 10 mL solvent A<br>

Extracted text: fraction remaining after a second extraction will be given by: VB Fx ((Px,ABVA+VB) (4) For n extractions, this can be generalized to: VB Fx ((Px,ABVA+VB)) (5) Since Fx < 1="" by="" definition,="" the="" efficiency="" should="" increase="" as="" the="" number="" of="" extractions="" increase.="" an="" interesting="" point="" to="" note="" about="" extraction="" efficiency="" can="" be="" illustrated="" in="" the="" following="" problem:="" compound="" x="" is="" dissolved="" in="" 100="" ml="" of="" solvent="" b,="" and="" extracted="" using="" solvent="" a.="" the="" partition="" coefficient="" pxab="" has="" a="" value="" of="" 5.00.="" what="" percentage="" of="" x="" remains="" in="" solvent="" b="" after:="" a="" single="" extraction="" of="" 100="" ml="" solvent="" a="" two="" extractions="" of="" 50="" ml="" solvent="" a="" five="" extractions="" of="" 20="" ml="" solvent="" a="" ten="" extractions="" of="" 10="" ml="" solvent="">

Jun 08, 2022
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