I need a one page with answers to the questions attached. No reference necessary.

Solution 1 :
A researcher assumes that the measurement D follows uniform distribution,
D ~ U [-1,1] with mean and variance defined as :
Mean :
Variance :
Sample D value =0.95
Part a.
Under uniform distribution, probability that the researcher obtains sample observations at least as large as the given D measurement value,
Part b .
Based on the probability value which stands quite low for a given sample observation. It is expected to be at least as large as the D measurement value then we might have to change the distributional assumptions to get better p value.
However, if we set the probability of the sample observations to be less than 0.95 than our distributional assumptions for uniform case stands better with a probability of 0.99795.
Solution 2. :
A coin is fair with sample size , n=10 , probability of getting a head or a tail is :
P(H) = P(T) = 0.5.
The occurrence of event: HHHHHHHHHT
Part a :
P(Measurement = 9 Heads, 1 Tail ) = 10C9 + 10C10
...