// initialize an array of ints int numbers[5] = {1,2,3,4,5}; int i = 0; 3 4 // print the address of the array variable printf("numbers = %p\n", numbers); 7 8 // print addresses of each array index 9....


Part 2:
Write a C program addressOfArray.c by inserting the code below in the main function.



1) Run the C program, attach a screenshot of the output in the answer sheet.


2) Attach the source code in the answer sheet


3) Then explain why the address after intvar is incremented by 4 bytes instead of 1 byte.



// initialize an array of ints<br>int numbers[5] = {1,2,3,4,5};<br>int i = 0;<br>3<br>4<br>// print the address of the array variable<br>printf(

Extracted text: // initialize an array of ints int numbers[5] = {1,2,3,4,5}; int i = 0; 3 4 // print the address of the array variable printf("numbers = %p\n", numbers); 7 8 // print addresses of each array index 9. 10 do { printf("numbers[%u] %p\n", i, (void *)(&numbers[i])); 11 i++; 12 } while (i < 5);="" print="" the="" size="" of="" the="" array="" printf("sizeof(numbers)="%lu\n",">

Jun 09, 2022
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