O Chapter 9 Hypothesis Tests for X A 5 https://egcc.instructure.com/courses/15697/assignments/366801 90% Q Search Using the normal approximation for the binomial distribution (without the continuity...

Thank youO Chapter 9 Hypothesis Tests for X<br>A 5 https://egcc.instructure.com/courses/15697/assignments/366801<br>90%<br>Q Search<br>Using the normal approximation for the binomial distribution (without the continuity correction), was is<br>the test statistic for this sample based on the sample proportion?<br>(Report answer as a decimal accurate to 3 decimal places.)<br>You are now ready to calculate the P-value for this sample.<br>P-value =<br>(Report answer as a decimal accurate to 4 decimal places.)<br>This P-value (and test statistic) leads to a decision to...<br>O reject the null<br>O accept the null<br>O fail to reject the null<br>O reject the alternative<br>As such, the final conclusion is that...<br>O There is sufficient evidence to warrant rejection of the assertion that there is a different<br>proportion of only children in the G&T program.<br>O There is not sufficient evidence to warrant rejection of the assertion that there is a different<br>proportion of only children in the G&T program.<br>O The sample data support the assertion that there is a different proportion of only children in the<br>GAT program.<br>O There is not sufficient sample evidence to support the assertion that there is a different proportion<br>of only children in the G&T program.<br>Question Help: Message instructor<br>Submit Question<br>re to search<br>

Extracted text: O Chapter 9 Hypothesis Tests for X A 5 https://egcc.instructure.com/courses/15697/assignments/366801 90% Q Search Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion? (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places.) This P-value (and test statistic) leads to a decision to... O reject the null O accept the null O fail to reject the null O reject the alternative As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. O There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. O The sample data support the assertion that there is a different proportion of only children in the GAT program. O There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program. Question Help: Message instructor Submit Question re to search
Question 9<br>In a certain school district, it was observed that 28% of the students in the element schools were<br>dassified as only children (no siblings). However, in the special program for talented and gifted children,<br>106 out of 325 students are only children. The school district administrators want to know if the<br>proportion of only children in the special program is significantly different from the proportion for the<br>school district. Test at the a = 0.05 level of significance.<br>What is the hypothesized population proportion for this test?<br>(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)<br>Based on the statement of this problem, how many tails would this hypothesis test have?<br>O one-tailed test<br>O two-tailed test<br>Choose the correct pair of hypotheses for this situation:<br>0.326 Ho:p== 0.326<br>Ho:p = 0.326 H:p<br>(D) (E) (F) H:p< 0.326 Ha:p + 0.326 Haip > 0.326<br>Ho:P<br>0.28 Ho:p = 0.28 Ho:p = 0.28<br>(A) (B) (C) H:p< 0.28 H.:p+ 0.28 Ha:p > 0.28<br>Using the normal approximation for the binomial distribution (without the continuity correction), was is<br>the test statistic for this sample based on the sample proportion?<br>(Report answer as a decimal accurate to 3 decimal places.)<br>You are now ready to calculate the P-value for this sample.<br>to search<br>E R<br>

Extracted text: Question 9 In a certain school district, it was observed that 28% of the students in the element schools were dassified as only children (no siblings). However, in the special program for talented and gifted children, 106 out of 325 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.05 level of significance. What is the hypothesized population proportion for this test? (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? O one-tailed test O two-tailed test Choose the correct pair of hypotheses for this situation: 0.326 Ho:p== 0.326 Ho:p = 0.326 H:p (D) (E) (F) H:p< 0.326="" ha:p="" +="" 0.326="" haip=""> 0.326 Ho:P 0.28 Ho:p = 0.28 Ho:p = 0.28 (A) (B) (C) H:p< 0.28="" h.:p+="" 0.28="" ha:p=""> 0.28 Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion? (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. to search E R
Jun 11, 2022
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