Suppose a marketing company randomly surveyed 439 households and found that in 259 of them, the woman made the majority of the purchasing decisions. Construct a 93% confidence interval for the...

Extracted text: Suppose a marketing company randomly surveyed 439 households and found that in 259 of them, the woman made the majority of the purchasing decisions. Construct a 93% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions. Margin of Error: E = We are 93% confident that the proportion of households in the population where women make the and majority of purchasing decisions is between || ||