- Questions & Answers
- Accounting
- Computer Science
- Automata or Computationing
- Computer Architecture
- Computer Graphics and Multimedia Applications
- Computer Network Security
- Data Structures
- Database Management System
- Design and Analysis of Algorithms
- Information Technology
- Linux Environment
- Networking
- Operating System
- Software Engineering
- Big Data
- Android
- iOS
- Matlab

- Economics
- Engineering
- Finance
- Thesis
- Management
- Science/Math
- Statistics
- Writing
- Dissertations
- Essays
- Programming
- Healthcare
- Law

- Log in | Sign up

The Student Union claims that a population mean amount of spending of undergraduate students at the college is $250 per trimester on textbooks with a population standard deviation of $54. To test this hypothesis, a random sample of 144 undergraduate students is polled and the amount each student spent on textbooks during the trimester is recorded. The sample mean is $260 per trimester on textbooks.

REQUIRED: a) At the 0.05 level of significance, is there evidence that the population mean amount of spending is different from $250 per trimester on textbooks? (3 marks)

At the 0.01 level of significance, is there evidence that the population mean amount of spending is different from $250per trimester on Mks? (3 marks)

REQUIRED: a) At the 0.05 level of significance, is there evidence that the population mean amount of spending is different from $250 per trimester on textbooks? (3 marks)

At the 0.01 level of significance, is there evidence that the population mean amount of spending is different from $250per trimester on Mks? (3 marks)

Answered Same DayDec 20, 2021

Q1

a.

H0: μ =250

H1: μ ≠ 250

The test statistic is z = ( 260-250)*144.5/54 = 2.22

with a 0.05 significance level and a two tail test the critical z value is 1.96

since the statistic value > critcal value we DO NOT ACCEPT the null hypothesis. There is no statistical evidence that mean spending in not $250

.

H0: μ =250

H1: μ ≠ 250

The test statistic is z = ( 260-250)*144.5/54 = 2.22

with a 0.01 significance level and a two tail test the critical z value is 2.576

since the statistic value < critcal value we ACCEPT the null hypothesis. There is statistical evidence that mean spending is $250.

c.

the diffrence in conclusions is due to the difference in type 1 e

or. this is the same as the...

a.

H0: μ =250

H1: μ ≠ 250

The test statistic is z = ( 260-250)*144.5/54 = 2.22

with a 0.05 significance level and a two tail test the critical z value is 1.96

since the statistic value > critcal value we DO NOT ACCEPT the null hypothesis. There is no statistical evidence that mean spending in not $250

.

H0: μ =250

H1: μ ≠ 250

The test statistic is z = ( 260-250)*144.5/54 = 2.22

with a 0.01 significance level and a two tail test the critical z value is 2.576

since the statistic value < critcal value we ACCEPT the null hypothesis. There is statistical evidence that mean spending is $250.

c.

the diffrence in conclusions is due to the difference in type 1 e

or. this is the same as the...

SOLUTION.PDF## Answer To This Question Is Available To Download

- A study by the department of Environmental Protection of NJ showed that the average number of airplanes flying through the town of Wayne is four per hour. Assume the passing of these airplanes through...SolvedJan 02, 2022
- Do Assignment/final exam. username: jjpanchal pass: dramma030 http://statistics101.onlineclasses.com/secure/406/7550577/index.htmSolvedDec 31, 2021
- MATH 218: Homework problems Homework 1. 1. Two dice are rolled. Introduce the following events: (1) E : “the sum is odd” (2) F : “at least one number is 1” (3) G : “the sum is 5” List the elementary...SolvedDec 31, 2021
- A PCB measurement at a low cost sampling station correctly detects a violation (i.e. themeasured PCB concentration exceeds a specified standard) for only 80% of the samples that areflagged as...SolvedDec 31, 2021
- Ina city in Italy, 30% of the families have a MasterCard, 20% have an AmericanExpress card, and 25% have a Visa card. Eight percent of families have both aMasterCard and an American Express card....SolvedDec 31, 2021
- 1) Using table G, find the values for CHI-square left and right if alpha = 0.01 and n = XXXXXXXXXXFind the 90% confidence interval for the variance and standard deviation if a sample of 15 has a standard...SolvedDec 31, 2021
- 1. Of all 3 – 5 year old children, 71% are enrolled in school.If a sample of 400 children are randomly selected, what is the probability thatat least 300 will be enrolled in school. 2. 5% of theater...SolvedDec 31, 2021
- n ? ? ? } 2 ? 1. The RVs X1, X2, …, Xn, Y1, Y2, …, Yn are independent and U(0, a)- distributed. Show that Z ? n?log? max{X(n) ,Y(n)}? has an Exp(1) distribution. ? min{X(n) ,Y(n) ? 2. Let X1, X2, … be...SolvedDec 29, 2021
- Mileage. A salesman who is on the road visiting clients thinks that, on average, he drives the same distance each day of the week. He keeps track of his mileage for several weeks and discovers that he...SolvedDec 29, 2021
- Absentees. The National Center for Education Statistics monitors many aspects of elementary and secondary education nationwide. Their 1996 numbers are often used as a baseline to assess changes. In...SolvedDec 29, 2021

Copy and Paste Your Assignment Here

Copyright © 2022. All rights reserved.