Using the floor plan below, calculate the heat loss in each room and the building heating load. Use the following data: Location: NYC, New York Indoor Design Temperature: 71 o F Walls: 8 in. concrete...

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Using the floor plan below, calculate the heat loss in each room and the building heating load. Use the following data:


Location: NYC, New York Indoor Design Temperature: 71 o F


Walls: 8 in. concrete block (density : 80 lbs/ft3 ), face brick, core insulation, 1/2 in. dry wall, vapor barrier, and R-5 insulation


Windows: Double glazed, aluminum frame, 3/8 in. air space (All windows are 3 ft - 6" high x 4 ft wide – Double hung)


Doors: 2" in. solid wood, 3 ft. wide x 7 ft. high Roof: 4 in. lightweight concrete, flat roof, finished ceiling, ceiling height: 10 ft.


The building is constructed on a concrete slab with R-5 edge insulation and has edge losses.


There is no mechanical ventilation. Include infiltration losses using the crack length method.


Assume a reasonable piping and pickup allowance.



Utility room Living room Alt windows 3-6" H x 4' W Scale 1/8 in. 1 ft-0 in. Kitchen Bath Bedroom No. 1 Bedroom No. 3 Bedroom No. 2

Answered 6 days AfterMay 14, 2022

Answer To: Using the floor plan below, calculate the heat loss in each room and the building heating load. Use...

Dr Shweta answered on May 21 2022
83 Votes
Solution
Given:
Indoor Design Temperature: 71 o F, Walls: 8 in. concrete block (density: 80 lbs/
ft3), 1/2 in. dry wall, Windows: Double glazed, 3/8 in. air space (All windows are 3 ft - 6" high x 4 ft wide – Double hung), Doors: 2" in. solid wood, 3 ft. wide x 7 ft. high Roof: 4 in. ceiling height: 10 ft.
To find:
1. The heat loss in each room
2. The building heating load
Solution:
1. The heat loss in each room is calculated by the following formula:
Q = A*U*(Ti-To) -------[1]
Here, Q =...
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