Extracted text: Values of Fa dfn 4 5 6 7 8 dfd 2 3 9. 0.10 39.86 49.50 53.59 55.83 57.24 58.20 58.91 59.44 59.86 0.05 161.45 199.50 215.71 224.58 230.16 233.99 236.77 238.88 240.54 1 0.025 647.79 799.50 864.16 899.58 921.85 937.1l 948.22 956.66 963.28 0.01 4052.2 4999.5 5403.4 5624.6 5763.6 5859.0 5928.4 5981.1 6022.5 0.005 16211 20000 21615 22500 23056 23437 23715 23925 24091 0.10 8.53 9.00 9.16 9.24 9.29 9.33 9.35 9.37 9.38 0.05 18.51 19.00 19.16 19.25 19.30 19.33 19.35 19.37 19.38 2 0.025 0.01 0.005 38.51 39.00 39.17 39.25 39.30 39.33 39.36 39.37 39.39 98.50 99.00 99.17 99.25 99.30 99.33 99.36 99.37 99.39 198.50 199.00 199.17 199.25 199.30 199.33 199.36 199.37 199.39 0.10 5.54 5.46 5.39 5.34 5.31 5.28 5.27 5.25 5.24 0.05 10.13 9.55 9.28 9.12 9.01 8.94 8.89 8.85 8.81 3 0.025 17.44 16.04 15.44 15. 10 14.88 14.73 14.62 14.54 14.47 0.01 34.12 30.82 29.46 28.71 28.24 27.91 27.67 27.49 27.35 0.005 55.55 49.80 47.47 46. 19 45.39 44.84 44.43 44.13 43.88 0.10 4.54 4.32 4.19 4.11 4.05 4.01 3.98 3.95 3.94 0.05 7.71 6.94 6.59 6.39 6.26 6.16 6.09 6.04 6.00 4 0.025 12.22 10.65 9.98 9.60 9.36 9.20 9.07 8.98 8.90 0.01 21.20 18.00 16.69 15.98 15.52 15.21 14.98 14.80 14.66 0.005 31.33 26.28 24.26 23.15 22.46 21.97 21.62 21.35 21.14 0.10 4.06 3.78 3.62 3.52 3.45 3.40 3.37 3.34 3.32 5. 19 7.39 0.05 6.61 5.79 5.41 5.05 4.95 4.88 4.82 4.77 5 0.025 10.01 8.43 7.76 7.15 6.98 6.85 6.76 6.68 0.01 16.26 13.27 12.06 11.39 10.97 10.67 10.46 10.29 10.16 0.005 22.78 18.31 16.53 15.56 14.94 14.51 14.20 13.96 13.77 0.10 3.78 3.46 3.29 3.18 3.11 3.05 3.01 2.98 2.96 0.05 5.99 5.14 4.76 4.53 4.39 4.28 4.21 4.15 4.10 6 0.025 8.81 7.26 6.60 6.23 5.99 5.82 5.70 5.60 5.52 0.01 13.75 10.92 9.78 9.15 8.75 8,47 8.26 8.10 7.98 0.005 18.63 14.54 12.92 12.03 I1.46 11.07 10.79 10.57 10.39 0.10 3.59 3.26 3.07 2.96 2.88 2.83 2.78 2.75 2.72 3.68 0.05 5.59 4.74 4.35 4. 12 3.97 3.87 3.79 3.73 7 0.025 8.07 6.54 5.89 5.52 5.29 5.12 4.99 4.90 4.82 9.55 12.40 0.01 12.25 8.45 7.85 7.46 7.19 6.99 6.84 6.72 0.005 16.24 10.88 10.05 9.52 9.16 8.89 8.68 8.51 0.10 3.46 3.11 2.92 281 2.73 2.67 2.62 2.59 2.56 0.05 5.32 4.46 4.07 3.84 3.69 3.58 3.50 3.44 3.39 8 0.025 0.01 7.57 6.06 5.42 5.05 4.82 4.65 4.53 4.43 4.36 11.26 8.65 7.59 7.01 6.63 6.37 6. 18 6.03 5.91 0.005 14.69 11.04 9.60 8.81 8.30 7.95 7.69 7.50 7.34
Extracted text: TITT The data shown to the right are from independent simple random samples from three populations. Use these data to complete parts (a) through (d). Sample 1| Sample 2| Sample 3 o 3 5 Click the icon to view a table of values of Fa. 6 2 14 a. Compute SST, SSTR, and SSE using the following computing formulas, where x, is the ith observation, n is the total number of observations, n; is the sample size for population j, and T; is the sum of the sample data from population j. SST = Ex? - (Ex)² /n, SSTR = E (T? /n) - (Ex)² /n, and sSE = SST -SSTR Compute the values required to find SST, SSTR, and SSE. n= Ex = Ex? = E(1; /n) = (Type integers or decimals. Do not round.) Calculate SST, SSTR, and SSE using the computing formulas. SST = (Type an integer or a decimal. Do not round.) SSTR= (Type an integer or a decimal. Do not round.) SSE = (Type an integer or a decimal. Do not round.) b. Compare your results in part (a) for SSTR and SSE with the following results from the defining formulas. SSTR Ση (-) and SSE = E(n - 1)s = the same value as when it is found by using the computing formula. When the value of SSE is found by using the defining formula, it When the value of SSTR is found by using the defining formula, it value as when it is found by using the computing formula. the same c. Construct a one-way ANOVA table. Source df MS F-statistic Treatment Error Total (Type integers or decimals rounded to two decimal places as needed.) d. Decide, at the 5% significance level, whether the data provide sufficient evidence to conclude that the means of the populations from which the samples were drawn are not all the same. First, let u,, Hz, and pa be the population means of samples 1, 2, and 3, respectively. What are the correct hypotheses for a one-way ANOVA test? OA. Ho: H1 =2 = H3 O B. Hg: H1 =H2 =H3 H: Not all the means are equal. O C. Ho: H1 #µ2 #H3 H: All the means are equal. O D. H,: H, H2 #H3 H H =2 =H3 Now determine the critical value F Fa = (Round to two decimal places as needed.) Finally, what is the correct conclusion? Since the F-statistic in the rejection region, Ho- The data sufficient evidence to conclude that the population means are not all the same.