1. Hydrogen gas at a pressure of 1.25 bar is contained in a thick-walled neoprene rubber sphere which has inner and outer radii of 70 mm and 80 mm, respectively. The concentration of hydrogen at the...

1 answer below »
1. Hydrogen gas at a pressure of 1.25 bar is contained in a thick-walled neoprene rubber sphere which has inner and outer radii of 70 mm and 80 mm, respectively. The concentration of hydrogen at the outer surface of the sphere is negligible and leakage is so small that steady-state conditions can be assumed to occur for a long time. The solubility of hydrogen in rubber is 2.37 × 10–3 kmol m–3 (bar)–1 and the diffusivity is 1.8 × 10–10 m2 s–1. Calculate the rate at which hydrogen escapes from the sphere. (Assume the inner surface of rubber is saturated with hydrogen.) 2. (a) Ammonia gas is being absorbed by water in a wetted-wall column. At one level of the column, the following data applies: gas-phase mass transfer coefficient 5.22 × 10–9 kmol m–2 s–1 Pa–1 liquid-phase mass transfer coefficient 3.88 × 10–5 m s–1 Henry's constant 0.955 kPa (kmol m–3)–1. Estimate the overall mass transfer coefficient KL. (b) What is the ratio of the individual mass transfer resistances in Question 2 (a)? (c) Use the following additional information to find the mass transfer flux in the column: mole fraction of ammonia in liquid* 1.351 × 10–3 mole fraction of ammonia in gas* 0.065 total pressure of system 1.013 bar mole mass of ammonia 17 *Note: these values will need to be converted to concentrations in kmol m–3. 2 Teesside University Open Learning (Engineering) © Teesside University 2011 (d) What is the partial pressure of the ammonia gas at the gas/liquid interface? (e) What is the molar concentration of the ammonia in the liquid at the interface? 3. Based on your experience or from reference books, choose a real industrial example of mass transfer which uses a column as its contacting device. Suggest reasons why the particular column was used in preference to other designs. 3 Teesside University Open Learning (Engineering) © Teesside University 2011 You will need two sheets of graph paper to complete 4. (a) Assuming that Raoult's law applies to all possible mixtures of two components, 'A' and 'B', plot a "pressure/composition" diagram at constant temperature T for the full range of mixtures from the data below. The diagram should show how the partial pressures of each component and the total pressure varies with composition. Data: Pure vapour pressure of 'A' at temperature T = 67 kPa Pure vapour pressure of 'B' at temperature T = 20 kPa (b) Using your diagram in (a), state the partial pressures and the total pressure at the reference temperature, of a mixture of 'A' and 'B' having 0.4 mole fraction 'A'. (c) Confirm these values using Raoult's law equation. (d) State what is meant by an 'Ideal liquid mixture'. (e) From an internet search, state what is meant by (i) 'negative deviation from ideality'. (ii) 'positive deviation from ideality'. 5. A mixture of octane and nonane containing 0.70 mole fraction (m.f.) octane, at its boiling point, is to be continuously separated in a distillation column. The top product is to have a composition of 0.98 m.f. octane and the bottom product must be no richer than 0.05 m.f. octane. The reflux ratio is set at 3 and the equilibrium data is given below. xoct 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 yoct 0.0 0.18 0.33 0.46 0.57 0.67 0.75 0.82 0.89 0.95 1.0 2 Teesside University Open Learning (Engineering) © Teesside University 2011 (a) Determine the number of theoretical plates required to perform the operation. (b) State which plate the feed should be introduced onto. (c) (i) What effect would altering the reflux ratio have on the number of plates required? (ii) In an actual industrial column, the number of plates is fixed at the design stage. In this case, what effect would a change in the reflux ratio have on the column's operation and how can this effect be used as a means of control? (d) If a packed column were to be used, determine the height of packing required, assuming an H.E.T.P. of 1.2 m. 6. (a) Write brief notes to explain what is meant by the following distillation techniques: (i) batch distillation (ii) continuous distillation (iii) simple (or single stage) distillation (iv) fractional (or multi-stage) distillation. (b) Select distillation techniques for the separation of the following mixtures, giving reasons for the techniques chosen. (i) 50 kg of a mixture of A (boiling point 160°C) and B (boiling point 405°C) where B is sensitive to heat. (ii) 500 kgh–1 of a mixture of C (boiling point 75°C) and D (boiling point 85°C). 3 Teesside University Open Learning (Engineering) © Teesside University 2011 7. 100 kmol of the mixture, whose equilibrium diagram is shown in FIGURE 1, is to be batch fractionally distilled until the contents of the still have been reduced to 0.20 mole fraction T. The still initially contains 0.70 mole fraction T. The column to be used has 3 theoretical stages and will be operated with a fixed reflux ratio of 3. Determine: (a) the amount of bottom product produced (b) the amount and composition of the overall top product removed. Hint: you will need to choose final distillate values between 0.6 and 0.99 mole fraction T. FIG. 1 Mole fraction T in liquid 0 0.2 0.4 0.6 0.8 1 Mole fraction T in vapour 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 0.1 0.3 0.5 0.7 0.9 4 Teesside University Open Learning (Engineering) © Teesside University 2011
Answered 10 days AfterMay 23, 2022

Answer To: 1. Hydrogen gas at a pressure of 1.25 bar is contained in a thick-walled neoprene rubber sphere...

Dr Shweta answered on Jun 02 2022
81 Votes
Answer 1.
Given: Inner radii of 70 mm = r1, outer radii of 70 mm = r2, pressure = 1.25 bar,
Solubility = 2.37 × 10–3 kmol m–3 (bar)–1, diffusivity = CA, 0= 1.8 × 10–10 m2 s–1, CA, L
= 0
To find: Calculate the rate at which hydrogen escapes from the sphere.
Solution: DAB = 2.37 × 10–3 * 1.25 = 2.9625 * 10-3 Kmol/m3
NA = C A, 0 – C A, L/1/4π DAB (1/r1-1/r2) = 4π DAB C A, 0/1/r1-1/r2 ----- [1]
On putting values in 1 we get,
= 4 *3.14 *2.9625 * 10-3 *1.8 × 10–10 /1/70-1/80
N A, r = 3.764 * 10-9 Kmol/s
η A, r = MA * N A, r
= 2 Kg/Kmol * 3.764 * 10-9 Kmol/s
η A, r = 7.528 *10-9 kg/s
Answer 2.
2a) given: Gas-phase mass transfer coefficient = KG = 5.22 × 10–9 kmol m–2 s–1 Pa–1
Liquid-phase mass transfer coefficient = KL = m s–1 = 3.88 × 10–5
Henry's constant = mH= 0.955 kPa (kmol m–3)–1
To calculate: the overall mass transfer coefficient KL
Solution: 1/KL= 1/mH KG + 1/ KL ----- [1]
On putting values in equation 1, we get
1/KL = 1/0.955*5.22 × 10–9 + 1/3.88 × 10–5
KL = 4.41 * 10-6 m/s
2b) Resistance offered by the liquid phase = 1/ KL
Resistance offered by the gas phase = 1/ mH * KG
Ratio of resistance offered by liquid to gas = 1/ KL/1/ mH * KG = mH * KG/ KL
Ratio = 0.955 * 5.22 × 10–9/3.88 × 10–5 = 0.14
2c) Given: mole fraction of ammonia in liquid χNH3 = 1.351 × 10–3
Mole fraction of ammonia in gas yNH3 = 0.065
Total pressure of system = 1.013 bar
Mole mass of ammonia 17
Total conc. = P/RT = 101.3/8.314 * 298 =0.0408 Kmol/m3
NA = KL (χNH3 – χg)CA = KL (CχNH3 – CA χg) = KL (CχNH3 – KG)
4.41 * 10-6 m/s (1.351 × 10–3 * 0.0408 – 0.065/0.955)
NA = 3.04 * 10-5 kmol/m2S
Mass flux = NA * M =3.04 * 10-5 * 17 = 5.17 * 10-4 Kg/m2S
2d) partial pressure of the ammonia gas at the gas/liquid interface is:
Partial pressure = PA = χA *P
On putting values, we get 0.065 * 101.3 bar= 6.58 bar
2e) Molar concentration of the ammonia in the...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here