2. Based on the tiles shown, how many moles of oxygen gas (O2) are needed to produce 36.04 grams of water (H20) when reacting with excess ethane in the equation 2C2H6 + 702 → 5CO2 + 6H20? 36.04gH0 1...

2. Based on the tiles shown, how many<br>moles of oxygen gas (O2) are needed to<br>produce 36.04 grams of water (H20) when<br>reacting with excess ethane in the<br>equation 2C2H6 + 702<br>→ 5CO2 + 6H20?<br>36.04gH0<br>1 mo,Q<br>7 mol O2<br>18.02 9H20<br>6 mot,Q<br>A. 19.0 moles of oxygen (O2)<br>B. 14.0 moles of oxygen (O2)<br>C. 2.3 moles of oxygen (02)<br>O D. 1.2 moles of oxygen (O2)<br>

Extracted text: 2. Based on the tiles shown, how many moles of oxygen gas (O2) are needed to produce 36.04 grams of water (H20) when reacting with excess ethane in the equation 2C2H6 + 702 → 5CO2 + 6H20? 36.04gH0 1 mo,Q 7 mol O2 18.02 9H20 6 mot,Q A. 19.0 moles of oxygen (O2) B. 14.0 moles of oxygen (O2) C. 2.3 moles of oxygen (02) O D. 1.2 moles of oxygen (O2)

Jun 10, 2022

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2. Based on the tiles shown, how many moles of oxygen gas (O2) are needed to produce 36.04 grams of water (H20) when reacting with excess ethane in the equation 2C2H6 + 702 → 5CO2 + 6H20? 36.04gH0 1...

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