Write a Short Lab Report for a conducted experiment on Voltaic Cell.A screen shots were provided of the Lab Manual. For your , procedure, part of the lab report process use,95-102 as pages. Short lab...

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Write a Short Lab Report for a conducted experiment on Voltaic Cell.A screen shots were provided of the Lab Manual. For your , procedure, part of the lab report process use,95-102 as pages. Short lab report samples are attached as reference.


Sample Chemistry 218 Laboratory Report Short Report Format Title: Acid Base Titrations — The Percentage of Acetic Acid in Vinegar By: A. Student, #990001 dd/mm/yy Lab Partner: M. Y. Partner Purpose: To use a quantitative titration method to determine the percentage of acetic acid in vinegar. Also to learn the concept of neutralization, moles, dilution, and stoichiometry as it applies to titration data. This was accomplished by first determining what volume of standard hydrochloric acid (of known concentration) will neutralize a known volume of sodium hydroxide of unknown concentration, using titration with the aid of a pH indicator (see Equation 1). Once the concentration of sodium hydroxide was standardized, it was used to determine the concentration of acetic acid in a diluted unknown vinegar solution (see Equation 2). A minor objective of the experiment was to learn how to properly clean, operate and read a burette. Equation 1: HCI (ag) + NaOH (aq) =<—— nacl="" (aq)="" +="" h,0="" ()="" +="" heat="" equation2:="" ch,cooh="" (ag)="" +="" naoh="" (ag)="===" ch,coo"="" na*="" (aq)="" +="" h,o="" (i)="" +="" heat="" procedure:="" the="" experiment="" was="" carried="" out="" as="" outlined="" in="" experiment="" r3="" of="" the="" chemistry="" 218="" laboratory="" manual,="" pp.="" xx-yy.="" note:="" 1.60="" g="" of="" naoh="" was="" dissolved="" in="" ~400="" ml="" water="" in="" part="" a="" step="" 1.="" otherwise="" no="" changes="" or="" modification="" were="" made.="" observations:="" part="" a.="" during="" titration="" of="" 0.1000="" m="" hci="" with="" unknown="" [naoh]:="" 1.="" cresol="" red="" ph="" indicator="" in="" hcl="" initially="" reddish-orange.="" 2.="" after="" addition="" of="" naoh,="" at="" the="" endpoint,="" solution="" was="" pink.="" part="" b.="" during="" titration="" of="" ch3cooh="" with="" standardized="" naoh:="" 1.="" phenolphthalein="" ph="" indicator="" in="" ch;cooh="" initially="" was="" clear="" and="" colourless.="" mass="" percentage="" of="" acetic="" acid="" in="" vinegar="" given:="" density="" of="" vinegar="1.005" g/ml="1.005" g/ml="" x="" 1000="" ml/l="1005" g/l="" therefore,="" 60.06="" g/l="" chscooh/1005="" g/l)="" x="" 100%="5.57%" ch3cooh="" in="" vinegar="" answers="" to="" questions:="" 1.="" write="" the="" net="" ionic="" equation="" for:="" a.="" hcl="" +="" naoh="" hci="" (aq)="" +="" naoh="" (aq)="~—" nacl="" (aq)="" +="" h,0="" (i)="" h*="" (aq)="" +="" ci"="" (aq)="" +="" na*="" +="" oh="" (aq)="—" na"="" (aq)="" +="" ci"="" (aq)="" +="" h,0="" (i)="" h*="" (ag)="" +="" oh="" (aq)="==" h,0="" ()="" b.="" acetic="" acid="" +="" naoh="" ch;cooh="" (aq)="" +="" naoh="" (aq)="==" ch,coo"="" na*="" (aq)="" +="" h,o="" (i)="" ch4;cooh="" (aq)="" +="" na*(aq)="" +="" oh"="" (ag)="==" ch;coo"="" na*="" (aq)="" +="" h,o0="" (i)="" ch,cooh="" (aq)="" +="" oh="" (aq)="">< ch;coo" (aq) + h,0 (i) conclusion: the percentage of acetic acid in vinegar was determined to be 5.57% (w/w). the concentration of the sodium hydroxide solution used to titrate the acetic acid was determined to be 0.1000 m. the titration method proved to be easy to perform and very precise in measuring concentrations of acids and bases. it is worthy of note that error was introduced into the percentage of acetic acid measurement because of the use of uncalibrated pipettes and burettes. ch;coo"="" (aq)="" +="" h,0="" (i)="" conclusion:="" the="" percentage="" of="" acetic="" acid="" in="" vinegar="" was="" determined="" to="" be="" 5.57%="" (w/w).="" the="" concentration="" of="" the="" sodium="" hydroxide="" solution="" used="" to="" titrate="" the="" acetic="" acid="" was="" determined="" to="" be="" 0.1000="" m.="" the="" titration="" method="" proved="" to="" be="" easy="" to="" perform="" and="" very="" precise="" in="" measuring="" concentrations="" of="" acids="" and="" bases.="" it="" is="" worthy="" of="" note="" that="" error="" was="" introduced="" into="" the="" percentage="" of="" acetic="" acid="" measurement="" because="" of="" the="" use="" of="" uncalibrated="" pipettes="" and="">
Answered 2 days AfterApr 18, 2024

Answer To: Write a Short Lab Report for a conducted experiment on Voltaic Cell.A screen shots were provided of...

Dr Shweta answered on Apr 21 2024
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Voltaic cell Experiment
1. Purpose of the experiment: The objective of this experiment is to construct multiple voltaic cells and quantify the elect
romotive force (emf), represented as Ecell, generated by each cell.
2. Introduction and Theory:
When zinc metal is introduced into a copper (II) sulfate solution, the zinc metal undergoes dissolution while metallic copper is precipitated. During this reaction, each zinc atom loses two electrons to become a zinc ion, which means that the zinc is undergoing oxidation. On the other hand, each copper (II) ion gains two electrons to become a copper atom, indicating that the copper (II) ions are being reduced to copper metal.
Zn (s) + CuSO4 (aq) Cu (s) + ZnSO4 (aq)
Zinc metal copper (II) sulfate copper metal zinc sulfate
To express these two processes, we can write the following half-equations:
Zn (s) Zn2+ (aq) + 2e- (aq)
Cu2+ (aq) + 2e- (aq) Cu (s)
Consequently, the entire procedure may be depicted as:
Zn (s) + Cu2+ (aq) Cu (s) + Zn2+ (aq)
In the aforementioned reaction, the electrons are immediately transported from the zinc metal to the copper (II) ions. In a basic voltaic cell, the species responsible for giving and receiving electrons are placed in separate containers called half-cells. In each half-cell, the metal involved is partially...
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