A student mixes 80.0 mL of 0.010 M Ba(NO)(aq) with 80.0 mL of 0.010 M NaSO(aq) both being strong electrolytes. Calculate the mass of BaSO(s) that precipitates from the solution: BaSO4(s) Ba^2+(aq) +...

A student mixes 80.0 mL of 0.010
M
Ba(NO)(aq) with 80.0 mL of 0.010
M
NaSO(aq) both being strong electrolytes.  Calculate the mass of BaSO(s) that precipitates from the solution:

BaSO4(s) <--> Ba^2+(aq) + SO4^2-(aq)       Ksp= 1.1x10^-10

if the molar mass of bariums sulfate is 233.38 g/mol.