AtypicalMesillaValleyirrigatorgrowscottonforwhichoutputispredictedwellbythisCobbDouglasproductionfunction:1Q=0.193L0.12W0.88WhereL=haofland;W=waterin1000cubicmetersappliedperseason;Q=tonsofcottonprodu...

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AtypicalMesillaValleyirrigatorgrowscottonforwhichoutputispredictedwellbythisCobbDouglasproductionfunction:1Q=0.193L0.12W0.88WhereL=haofland;W=waterin1000cubicmetersappliedperseason;Q=tonsofcottonproducedperseason.1.1Writetheproductionfunctionforagrowerwhosefarmislimitedto1haofland.Forthatlittlefarm,howmuchwaterisneededtoproduce1.2tonsoftotalcotton?1.2Howmuchwaterappliedtocottonisneededtoproduce1.2tonscottonifthegrowerallocatesonequarterofthefarm(0.25haofland)tootheruses?Whatifthegrowerassigns0.50haoflandtootheruses?Whydoesittakeasmallerincreaseinwaterusetomaintaincottonproductionwhenlandfallsfrom1.00to0.75hathanwhenlandfallfrom0.75to0.50ha?1.3Noticethatahigherwater‐to‐landratio(higherwaterappliedperha)canmaintainthebaselevelofcottonproduction(1.20).Productionismaintainedbysubstitutingwaterforland.Thisiscalledthe“lawofvariableproportions,”animportantinsightofmicroeconomictheory.Describeforfarmers,researchers,andpolicymakerswhythisisanimportantinsight.1.4Whatadditionalinformationdoestheirrigatorneedtofindhowmuchwaterandlandminimizesthecostofproducing1.20tonsofcotton?1.5Writetheequationsforthemarginalphysicalproductivityofwater.Showthatwater’smarginalproductivityisdiminishingwithincreasedwater.Showthatthisproductionfunctionhasconstantreturnstoscale.1.6Whatisthemarginalrateoftechnicalsubstitutionofwaterforlandwhenlandisfixedat1haandwaterappliedis8.04?WhatusefulinformationdoesthatMRTStellyou?ShowthatinputusemustoccurinstageIIofproduction.1.7Showthatthemarginalphysicalproductofwaterdependsononlytheratioofwaterappliedtolandandnotontheabsolutelevelofeither.1.8Canyouusethisproductionfunctiontofindtheprofitmaximizinglevelofirrigation(appliedwater)fora1hafarm?Whattwopiecesofextrainformationdoyouneed?
Answered 1 days AfterOct 12, 2021

Answer To: AtypicalMesillaValleyirrigatorgrowscottonforwhichoutputispredictedwellbythisCobbDouglasproductionfun...

Komalavalli answered on Oct 14 2021
121 Votes
CHAPTER 9 HW
1.Q = 0.193 L0.12W0.88
1.1
L = 1
Q =1.2
W =( Q/(0.193 L0.12))1.14
W = (1.2/0.193
(1)0.12)1.14
W = 8
Therefore to produce 1.2 tons of cotton , the water required is 8000 cubic meters.
1.2
L = 0.75
Q =1.2
W =( Q/(0.193 L0.12))1.14
W = (1.2/0.193(0.75)0.12)1.14
W = 8.35
L = 0.50
L = 0.75
Q =1.2
W =( Q/(0.193 L0.12))1.14
W = (1.2/0.193(0.75)0.12)1.14
W = 8.82
To keep constant output decreasing one variable...
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