answer the question and give the mutiple choice answer
Last Name: First name: Student ID: Assignment: Date: • 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc Ø Please put your answers to the questions in this bubble sheet. Ø Only your bubble sheet will be evaluated. Please upload ONLY your bubble sheet on D2L. Ø Please provide ONLY one answer for each question. More than one answer for each question will not be evaluated. Ø There are no negative points for incorrect answers. October 15, 2021, 11:59 PM is the deadline for submitting your bubble sheet on D2L. e e 1. Alice and Bob want to communicate at faster-than-light speeds as they are separated very far from each other. They intend to use the collapse of the quantum state to do so. Will they succeed? Why or why not? a). No, they won’t succeed because the collapse of the quantum state does not exist, and it is simply an illusion. b). Yes, they will succeed because the collapse of the quantum state does allow superluminal communication. c). No, they won’t succeed because the collapse of the quantum state generates uncontrollable results, which makes superluminal communication impossible. d). No, they won’t succeed because the collapse of the quantum state still happens at the speed of light. 2. Which statement below is correct? a). Interference occurs whenever there are multiple histories leading to the same outcome. b). Interference only occurs when the different histories leading to the same outcome are distinguishable. c). In the C60 experiment, collisions of the C60 molecules with background atoms make the interference disappear because they strongly perturb the trajectory of the C60 molecules. d). In the C60 experiment, the emission of photons by the molecules makes the interference fringes disappear because the photons contain information about the path of the molecules. 3. In the diagram below, when the upper path is extended by length L, then all photons are detected in D1. What happens to the probabilities for detector D1 and D2 if the extension becomes 2L? a). D1: 0%, D2: 100% b). D1: 100%, D2: 0% c). D1: 50%, D2: 50% d). D1: 25%, D2: 75%. 4. In the diagram below, what are the detection probabilities of D1, D2, D3 and D4? (Here, ?/2 denotes an extension by half a wavelength.) a). D1: 25%, D2: 25%, D3: 25%, D4: 25% b). D1: 50%, D2: 0%, D3: 25%, D4: 25% c). D1: 0%, D2: 50% , D3: 0%, D4: 50% d). D1: 50%, D2: 0%, D3: 0%, D4: 50% e). D1:50%, D2: 0%, D3: 50%, D4: 0%. D4 BS1 BS2 Incident photon D 1 M1 BS3 BS3 BS4 D 2 D 3 M2 NDD 5- In the experiment below, what are the probabilities for the photon to be detected by D1 and D4? Mirror, M; Beam Splitter, BS; Detector, D. NDD is a non-destructive detector. a) D1: 1/4, D4: 3/8 b) D1: 3/8 , D4: 1/4 - 1/(4√2) c) D1: 3/8, D4: 1/4 + 1/(4√2) d) D1: 1/4, D4: 1/4 D3 BS1 BS2 Incident photon M1 BS6 D2 M3 M2 D1 NDD 6- In the experiment below, what are the probabilities for the photon to be detected by D2 and D3? Mirror, M; Beam Splitter, BS; Detector, D; Obstacle, . NDD is a non-destructive detector. a) D2: 1/8, D3: 9/16 b) D2: 5/16, D3: 5/16 c) D2: 5/16, D3: 9/16 d) D2: 1/8, D3: 3/8 7. In the diagram below, what are the detection probabilities of D1, D2, D3 and D4? (Here, NDD is a non-destructive detector.) a). D1: 50%, D2: 0%, D3: 50%, D4: 0% b). D1: 25%, D2: 25%, D3: 50%, D4: 0% c). D1: 25%, D2: 25% , D3: 25%, D4: 25% d). D1: 0%, D2: 50%, D3: 25%, D4: 25% e). D1:50%, D2: 0%, D3: 25%, D4: 25%. 8. In the diagram below, what is the probability of the detection outcome A’2-B’1 ? (Here, ?/2 denotes an extension by half a wavelength.) a). 50% b). 0% c). 25% d). 100% D3 BS1 BS2 Incident photon M1 BS6 D 1 D4 M2 D2 M3 BS3 BS4 BS5 NDD 9- In the experiment below, what are the probabilities for the photon to be detected by D2 and D3? Mirror, M; Beam Splitter, BS; Detector, D. NDD is a non- destructive detector. Here, the extension between M2 and BS5 adds a quarter of the photon’s wavelength to the path. a) D2: 1/2, D3: 1/4 - 1/(4√2) b) D2: 1/4, D3: 1/4 - 1/(4√2) c) D2: 1/4, D3: 1/4 + 1/(4√2) d) D2: 1/2, D3: 1/4 + 1/(4√2) ?/4 D3 BS1 BS2 Incident photon M1 BS6 D 1 D4 M2 D2 M3 BS3 BS4 BS5 NDD 10- In the same setup as Q9 above, what are the probabilities for the photon to be detected by D1 and D4 when the NDD operates as before, but the computer monitor reporting the results to the human experimentalist is broken? a) D1: 1/2, D4: 1/4 - 1/(4√2) b) D1: 1/4, D4: 1/4 - 1/(4√2) c) D1: 1/4, D4: 1/4 + 1/(4√2) d) D1: 1/2, D4: 1/4 + 1/(4√2) ?/4 Last Name: First name: Student ID: Assignment: Date: • 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc a b dc Ø Please put your answers to the questions in this bubble sheet. Ø Only your bubble sheet will be evaluated. Please upload ONLY your bubble sheet on D2L. Ø Please provide ONLY one answer for each question. More than one answer for each question will not be evaluated. Ø There are no negative points for incorrect answers. October 15, 2021, 11:59 PM is the deadline for submitting your bubble sheet on D2L. e e 1. Alice and Bob want to communicate at faster-than-light speeds as they are separated very far from each other. They intend to use the collapse of the quantum state to do so. Will they succeed? Why or why not? a). No, they won’t succeed because the collapse of the quantum state does not exist, and it is simply an illusion. b). Yes, they will succeed because the collapse of the quantum state does allow superluminal communication. c). No, they won’t succeed because the collapse of the quantum state generates uncontrollable results, which makes superluminal communication impossible. d). No, they won’t succeed because the collapse of the quantum state still happens at the speed of light. 2. Which statement below is correct? a). Interference occurs whenever there are multiple histories leading to the same outcome. b). Interference only occurs when the different histories leading to the same outcome are distinguishable. c). In the C60 experiment, collisions of the C60 molecules with background atoms make the interference disappear because they strongly perturb the trajectory of the C60 molecules. d). In the C60 experiment, the emission of photons by the molecules makes the interference fringes disappear because the photons contain information about the path of the molecules. 3. In the diagram below, when the upper path is extended by length L, then all photons are detected in D1. What happens to the probabilities for detector D1 and D2 if the extension becomes 2L? a). D1: 0%, D2: 100% b). D1: 100%, D2: 0% c). D1: 50%, D2: 50% d). D1: 25%, D2: 75%. 4. In the diagram below, what are the detection probabilities of D1, D2, D3 and D4? (Here, ?/2 denotes an extension by half a wavelength.) a). D1: 25%, D2: 25%, D3: 25%, D4: 25% b). D1: 50%, D2: 0%, D3: 25%, D4: 25% c). D1: 0%, D2: 50% , D3: 0%, D4: 50% d). D1: 50%, D2: 0%, D3: 0%, D4: 50% e). D1:50%, D2: 0%, D3: 50%, D4: 0%. D4 BS1 BS2 Incident photon D 1 M1 BS3 BS3 BS4 D 2 D 3 M2 NDD 5- In the experiment below, what are the probabilities for the photon to be detected by D1 and D4? Mirror, M; Beam Splitter, BS; Detector, D. NDD is a non-destructive detector. a) D1: 1/4, D4: 3/8 b) D1: 3/8 , D4: 1/4 - 1/(4√2) c) D1: 3/8, D4: 1/4 + 1/(4√2) d) D1: 1/4, D4: 1/4 D3 BS1 BS2 Incident photon M1 BS6 D2 M3 M2 D1 NDD 6- In the experiment below, what are the probabilities for the photon to be detected by D2 and D3? Mirror, M; Beam Splitter, BS; Detector, D; Obstacle, . NDD is a non-destructive detector. a) D2: 1/8, D3: 9/16 b) D2: 5/16, D3: 5/16 c) D2: 5/16, D3: 9/16 d) D2: 1/8, D3: 3/8 7. In the diagram below, what are the detection probabilities of D1, D2, D3 and D4? (Here, NDD is a non-destructive detector.) a). D1: 50%, D2: 0%, D3: 50%, D4: 0% b). D1: 25%, D2: 25%, D3: 50%, D4: 0% c). D1: 25%, D2: 25% , D3: 25%, D4: 25% d). D1: 0%, D2: 50%, D3: 25%, D4: 25% e). D1:50%, D2: 0%, D3: 25%, D4: 25%. 8. In the diagram below, what is the probability of the detection outcome A’2-B’1 ? (Here, ?/2 denotes an extension by half a wavelength.) a). 50% b). 0% c). 25% d). 100% D3 BS1 BS2 Incident photon M1 BS6 D 1 D4 M2 D2 M3 BS3 BS4 BS5