() Combustion geaction of CctHio ong) (b) For CoHio | mole= 82 g | mol 829 82g I mol Converting goam to mole 45gx I mol. 0.548 82 For O2 | mole 32 | mol =1 32g = | | mol Converting gram to mole 156gx...

Use dimensional analysis to show all work:

How many grams of excess reagent is used and how many grams remain?

A student made 102 g of carbon dioxide what is her % yield?

(Rest of work provided on images.)

Extracted text: () Combustion geaction of CctHio ong) (b) For CoHio | mole= 82 g | mol 829 82g I mol Converting goam to mole 45gx I mol. 0.548 82 For O2 | mole 32 | mol =1 32g = | | mol Converting gram to mole 156gx I mol 3zg 4.875


Extracted text: From the reaction I mol CoHio veact with mol O2 0.548 mol CaHio react wth 17 x 0:548 mol 0, 4. 658 mol o limting reacfart = CsHio I mol Cotio produce 5 mol (02 .'. 0.548 mol cotHio produce: 5x0.548 P.14 mol (a I mote Co2 44 | mol -1 44 = 1 mol Conventing mel to gram 2.74 mol X 44 g 1 mol = 130.56 g O Limbting Reactant= Cg Hio