Please use CISCO Packet Tracer to build the following network: Use a Class - C IP Address XXXXXXXXXX/24 to create 3 Departments (subnets) Sales, HR, and IT. Each Department will have 4 end devices: 1....

Network Diagram                                        17
High Level Network Diagram
Deportments: Sales, HR and IT
Introduction
Network Diagram:
In this assignment, I’m building the communication between the Sales, HR and IT deportment.
All deportment are connected with address 192.168.3.0/24 and user devices would get Auto IP address from concern deportment DHCP server.
Equipment’s used:
Gateway Router: Cisco 2911
Access switches: Cisco 2950-24 * 3 (One switch for each deportment)
DHCP Servers: Server *3 (One server for each deportment)
User PC: PC * 3 (One pc for each user)
Laptop: Lap * 3 (One lap for each user)
Printer: One printer for each deportment)
All connected with Cross over cables
VLAN Information’s:
Sales deportment: VLAN 10
HR Deportment: VLAN 20
IT Deportment: VLAN 30
Gateway Router:
Interface details:
    Deportment
    Hostname
    Device name
    Interface
    Subnet
    SALES
    Router
    GATEWAY
    Gigabit interface 0/0
SVI: VLAN10
Gigabit interface 0/0.10
    192.168.3.1/26
    HR
    
    
    Gigabit interface 0/1
SVI: VLAN20
Gigabit interface 0/1.20
    192.168.3.65/26
    IT
    
    
    Gigabit interface 0/2
SVI: VLAN30
Gigabit interface 0/2.1
    192.168.3.129/26
Subnet Details:
Class-C IP Address: 192.162.3.0/24 subnet ID (Network Address)
Default Subnet Mask: 255.255.255.0
1111 1111 . 1111 1111 . 1111 1111 . 0000 0000 Binary Mask
Class-C : N.N.N.H = N.N.N.---- ----
Subnetting = Borrow Bits from the Host Portion of the IP Address
N.N.N.sshh hhhh/24+2=/26
128 64 32 16 8421
---- ----
New Mask: 255.255.255.1100 0000 = 255.255.255.192
Department Names:
Sales     4 End Devices: Desktop, Laptop, Printer, & Server
HR    4 End Devices: Desktop, Laptop, Printer, & Server
IT    4 End Devices: Desktop, Laptop, Printer, & Server
Subnetting: borrow bits from the HOST portion of IP Address
Law#0 Subnet size
192.162.3.0/26 /n = /26
subnet size = 2^(32-/n) = 2^(32-26) = 2^6 = 64 total ip addresses
Law#1: 2^(borrowed bits) = # of Subnets
x =1,2,3,4, ...., 8
2^X = 2^2 = 4 subnets ~ 3 subnets or more
192.162.3.sshh hhhh
2^2 = 4 subnets
Law#2: 2^(hosts bits) - 2(NA+BA) = # of valid hosts per subnet
(2^6) - 2 = 64 - 2 = 62 valid hosts per subnet
N.N.N.sshh hhhh
128 64
SS
--
00 = .0 = 192.162.3.0000 0000 = 192.162.3.0 = Sales
01 = .64 = 192.162.3.0100 0000 = 192.162.3.64 = HR
10 = .128 =...