Consider the circuit below. The battery has an open-circuit voltage of ɛ = 30 V and an internal resistance ofr = 1N. R2 = 18.00 N E = 30.00 V R1 9.00 N %3D ir = 1.00 N R3 10.00 N R5 8.00 N R4 = 10.00...

Extracted text: Consider the circuit below. The battery has an open-circuit voltage of ɛ = 30 V and an internal resistance ofr = 1N. R2 = 18.00 N E = 30.00 V R1 9.00 N %3D ir = 1.00 N R3 10.00 N R5 8.00 N R4 = 10.00 N Hint a. Find the equivalent resistance of the circuit (not including the internal resistance). Reg b. Find the current out of the battery (do not ignore the internal resistance). Ibat A c. Find the potential drop across each resistor. o Across Rj and R2: AV = V. Across R3 and R4: AV = V. Across Rs: Д V — V. Across r: AV = V. (These drops should add up to the value of ɛ.) d. Find the currents through Rị and R2: IRI A IR2 A e. Find the currents through R3 and R4: IR3 А IRA A f. What is the percentage of the total power supplied by the battery that is dissipated in the internal resistance of the battery? A total of % of the total power supplied by the battery is dissipated in the internal resistance r. 十