Question 1.b of 1 Submit Consider the reaction of 30.0 mL of 0.244 M Bal, with 20.0 mL of 0.315 M Na;PO4. Since the precipitate is Ba3(POa)2, write the molecular equation for the precipitation...

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Question 1.b of 1<br>Submit<br>Consider the reaction of 30.0 mL of<br>0.244 M Bal, with 20.0 mL of 0.315<br>M Na;PO4.<br>Since the precipitate is Ba3(POa)2,<br>write the molecular equation for the<br>precipitation reaction. If no reaction<br>occurs, write NR after the reaction<br>arrow.<br>3 Bal2(aq) + 2 Na,PO.(aq) → Ba3(PO.)<br>2(s) + 6 Nal2(aq)<br>2-<br>3C.<br>Reset<br>><br>1<br>2<br>3<br>4<br>7<br>8<br>9<br>(<br>)<br>(s)<br>(1)<br>(g)<br>(aq)<br>Na<br>Ва<br>NR<br>• x H2O<br>Tap here or pull up for additional resources<br>1L<br>LO<br>+<br>

Extracted text: Question 1.b of 1 Submit Consider the reaction of 30.0 mL of 0.244 M Bal, with 20.0 mL of 0.315 M Na;PO4. Since the precipitate is Ba3(POa)2, write the molecular equation for the precipitation reaction. If no reaction occurs, write NR after the reaction arrow. 3 Bal2(aq) + 2 Na,PO.(aq) → Ba3(PO.) 2(s) + 6 Nal2(aq) 2- 3C. Reset > 1 2 3 4 7 8 9 ( ) (s) (1) (g) (aq) Na Ва NR • x H2O Tap here or pull up for additional resources 1L LO +

Jun 10, 2022

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Question 1.b of 1 Submit Consider the reaction of 30.0 mL of 0.244 M Bal, with 20.0 mL of 0.315 M Na;PO4. Since the precipitate is Ba3(POa)2, write the molecular equation for the precipitation...

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