Siegbert runs a hot dog stand that opens at 8 A.M. From 8 until 11 A.M. customers seem to arrive, on the average, at a steadily increasing rate that starts with an initial rate of 5 customers per hour...

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Siegbert runs a hot dog stand that opens at 8 A.M. From 8 until 11 A.M. customers seem to arrive, on the average, at a steadily increasing rate that starts with an initial rate of 5 customers per hour at 8 A.M. and reaches a maximum of 20 customers per hour at 11 A.M. From 11 A.M. until 1 P.M. the (average) rate seems to remain constant at 20 customers per hour. However, the (average) arrival rate then drops steadily from 1 P.M. until closing time at 5 P.M. at which time it has the value of 12 customers per hour. If we assume that the numbers of customers arriving at Siegbert’s stand during disjoint time periods are independent, then what is a good probability model for the preceding? What is the probability that no customers arrive between 8:30 A.M. and 9:30 A.M. on Monday morning? What is the expected number of arrivals in this period?



Answered Same DayDec 24, 2021

Answer To: Siegbert runs a hot dog stand that opens at 8 A.M. From 8 until 11 A.M. customers seem to arrive, on...

David answered on Dec 24 2021
107 Votes
From 8 AM to 11 AM, there is increase of 5 customers per hour which means increase of 2.5 customer

per 30 minutes.
5
11 AM 1 PM 5 PM8 AM
20
12.5
8.30
AM
9.30
AM
7.5

Area between 8 .30 AM to 9.30 AM = ½ * 1* (12.5-7.5) + 7.5* 1 = 10 customers on average
Probability that no...
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