Determine the nominal axial compressive strength for the following cases conforming to AISC Requirements: L = 15 FT L = 20 FT W10 x 33 L A992 steel A992 STEEL: Fy = 50 ksi and Fu = 65 ksi W10x33 A =...


Determine the nominal axial compressive strength for the following cases conforming to AISC Requirements:



  1. L = 15 FT

  2. L = 20 FT


W10 x 33<br>L<br>A992 steel<br>A992 STEEL: Fy = 50 ksi and Fu = 65 ksi<br>

Extracted text: W10 x 33 L A992 steel A992 STEEL: Fy = 50 ksi and Fu = 65 ksi
W10x33<br>A =<br>9.71<br>in.^2<br>d =<br>9.730<br>in.<br>tw =<br>0.290<br>in.<br>bf =<br>7.960<br>in.<br>tf =<br>0.435<br>in.<br>T =<br>7-1/2<br>in.<br>k =<br>0.9350<br>in.<br>in.<br>k1 =<br>0.7500<br>gage =<br>5-1/2<br>in.<br>rt =<br>2.140<br>in.<br>d/Af =<br>2.81<br>Ix =<br>Sx =<br>171.00<br>in. ^4<br>35.00<br>in.^3<br>rx<br>4.190<br>in.<br>ly =<br>Sy =<br>36.60<br>in.^4<br>9.20<br>in. ^3<br>ry =|<br>1.940<br>in.<br>I| ||<br>

Extracted text: W10x33 A = 9.71 in.^2 d = 9.730 in. tw = 0.290 in. bf = 7.960 in. tf = 0.435 in. T = 7-1/2 in. k = 0.9350 in. in. k1 = 0.7500 gage = 5-1/2 in. rt = 2.140 in. d/Af = 2.81 Ix = Sx = 171.00 in. ^4 35.00 in.^3 rx 4.190 in. ly = Sy = 36.60 in.^4 9.20 in. ^3 ry =| 1.940 in. I| ||

Jun 11, 2022
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