A smart phone manufacturer is interested in constructing a 95% confidence interval for the proportion of smart phones that break before the warranty expires. 83 of the 1560 randomly selected smart...


A smart phone manufacturer is interested in<br>constructing a 95% confidence interval for the<br>proportion of smart phones that break before<br>the warranty expires. 83 of the 1560 randomly<br>selected smart phones broke before the<br>warranty expired. Round answers to 4 decimal<br>places where possible.<br>a. With 95% confidence the proportion of all<br>smart phones that break before the warranty<br>expires is between<br>and<br>b. If many groups of 1560 randomly selected<br>smart phones are selected, then a different<br>confidence interval would be produced for<br>each group. About<br>percent of these<br>confidence intervals will contain the true<br>population proportion of all smart phones that<br>break before the warranty expires and about<br>percent will not contain the true<br>nonulation pronortion<br>

Extracted text: A smart phone manufacturer is interested in constructing a 95% confidence interval for the proportion of smart phones that break before the warranty expires. 83 of the 1560 randomly selected smart phones broke before the warranty expired. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all smart phones that break before the warranty expires is between and b. If many groups of 1560 randomly selected smart phones are selected, then a different confidence interval would be produced for each group. About percent of these confidence intervals will contain the true population proportion of all smart phones that break before the warranty expires and about percent will not contain the true nonulation pronortion

Jun 11, 2022
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