determine if the frequency of deficiencies of variable (medication errors) are statistically significantly different between for-profit and non-profit nursing homes, interpret the results for the...


determine if the frequency of deficiencies of variable (medication errors) are statistically significantly different between for-profit and non-profit nursing homes, interpret the results for the chi-square?


Crosstab<br>Count<br>for profit=1, nonprofit and<br>GV=0<br>.00<br>1.00<br>Total<br>Medication errors > 5%<br>112<br>264<br>376<br>1<br>5<br>19<br>24<br>Total<br>117<br>283<br>400<br>Chi-Square Tests<br>Asymptotic<br>Significance<br>(2-sided)<br>Exact Sig.<br>(2-sided)<br>Exact Sig.<br>(1-sided)<br>Value<br>df<br>Pearson Chi-Square<br>.874<br>1<br>.350<br>Continuity Correction<br>.495<br>.482<br>Likelihood Ratio<br>.930<br>1<br>.335<br>Fisher's Exact Test<br>.488<br>.246<br>Linear-by-Linear<br>Association<br>.872<br>1<br>.350<br>N of Valid Cases<br>a. O cells (0.0%) have expected count less than 5. The minimum expected count is 7.02.<br>400<br>b. Computed only for a 2x2 table<br>

Extracted text: Crosstab Count for profit=1, nonprofit and GV=0 .00 1.00 Total Medication errors > 5% 112 264 376 1 5 19 24 Total 117 283 400 Chi-Square Tests Asymptotic Significance (2-sided) Exact Sig. (2-sided) Exact Sig. (1-sided) Value df Pearson Chi-Square .874 1 .350 Continuity Correction .495 .482 Likelihood Ratio .930 1 .335 Fisher's Exact Test .488 .246 Linear-by-Linear Association .872 1 .350 N of Valid Cases a. O cells (0.0%) have expected count less than 5. The minimum expected count is 7.02. 400 b. Computed only for a 2x2 table

Jun 08, 2022
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