Did I calculate this correctly? Thank you. 1.96(b) z>1.962- - 1,962=1.96(c) z 1.6452く -1,96 orz71.96(d) z>1.645(e) z 1.2813. Find the p – value for this problem. Show your work and circle your...

Did I calculate this correctly? Thank you.

Extracted text: P=•38 n= 500 Use the following to answer questions 10, 11, 12, 13, and 14. According to a report in USA Today, 38% of U.S. women wear size 7 shoes. A mail X = 69 order catalog company took a random sample of 500 orders for women's shoes, and found that 169 of the orders were for size 7 shoes. 10. Set up the correct null and alternative hypotheses to test if these data indicate that the proportion of order size 7 shoes from the catalog is different from the proportion of women wearing size 7 shoes in the general population. Ho : vs H. : n=500 ×こ167 P= =.338 P=,38 500 Pニ,34262 %3D =o62 11. Calculate the value of the test statistic. Show your work and circle your answer. 2* - ア-P (. 3५ -.१8 %3D -1.84 r638)(.62) 500 z=ー1.84 a-025 12. Identify the rejection region, using a =0.05 d=.0a5 (a) z<-1.96 or="" z="">1.96 (b) z>1.96 2- - 1,96 2=1.96 (c) z<-1.645 or="" z="">1.645 2く -1,96 orz71.96 (d) z>1.645 (e) z<-1.28 or="" z="">1.28 13. Find the p – value for this problem. Show your work and circle your answer. use test statistic p-valne • 0329 Value t.0329 0658 •0658 .0329 0329 2=-1,84 z* = 1.84 ( P-value = 14. Comparing the p-value you found in question 13, with a=0.05, State your decision, draw your conclusion, and interpret your conclusion in the context of the problem. Decision: Fail to 'reject Ho Conclusion: There is not sufticient evidence at the alpha level of Ooo5 to canclude that the forfortion of women we ig not 3890. wearing Size 2 shoes P-value = ,045s>a= 0.05 e value is qeaten than alpha value so we fail to rejeet Ho