Go to : www.pearsonmylabs.com"Sign in"User: Karate94Password: Shadow50Statistics is the classSelect "View all assignments"Scroll down to "M7 Quiz"Statistics is the class.I have attached samples and instructions of what types of problems will be on the quiz.
7/14/2019 M6 MyStatLab Assignment-Dylan Boccardo https://xlitemprod.pearsoncmg.com/api/v1/print/math 1/1 Student: Dylan Boccardo Date: 07/14/19 Instructor: Pamela Kimbrough Course: Statistics, Summer 2019 - B Term, Coordinator, Sec. B03 Assignment: M6 MyStatLab Assignment Determine whether each of the following variables would best be modeled as continuous or discrete. a. The number of phone calls made in a day b. The number of guests at a wedding c. The number of turtles in a pond d. The area of a postage stamp e. The distance a javelin is thrown Discrete outcomes (or discrete variables) are numerical values that you can list or count. Continuous outcomes (or continuous variables) cannot be listed or counted because they occur over a range. a. The number of phone calls made in a day is because phone calls can be counted.discrete b. The number of guests at a wedding is because guests can be counted.discrete c. The number of turtles in a pond is because turtles can be counted.discrete d. The area of a postage stamp is because area occurs over a range without gaps or interruptions.continuous e. The distance a javelin is thrown is because distance occurs over a range without gaps or interruptions.continuous 7/14/2019 M7 MyStatLab Assignment-Dylan Boccardo https://xlitemprod.pearsoncmg.com/api/v1/print/math 1/1 Student: Dylan Boccardo Date: 07/14/19 Instructor: Pamela Kimbrough Course: Statistics, Summer 2019 - B Term, Coordinator, Sec. B03 Assignment: M7 MyStatLab Assignment According to a poll, % of Americans read print books exclusively (rather than reading some digital books). Suppose a random sample of Americans is selected. Complete parts (a) through (d) below. 37 900 a. What percentage of the sample would we expect to read print books exclusively? The expected percentage of Americans who read prink books exclusively is equal to the population percentage of Americans who read prink books exclusively. The population percentage is %.37 Thus, we should expect % of Americans to read prink books exclusively. 37 b. Verify that the conditions of the Central Limit Theorem are met. To determine whether the Central Limit Theorem can be applied here, three conditions must hold for the sample: the Random and Independent condition, the Large Samples condition, and the Big Populations condition. The Random and Independent condition requires that the sample is randomly drawn from its population and observations are independent of each other. It can be reasonably assumed that the sample is randomly drawn from its population, and that the observations are independent of each other. The Large Samples condition requires that at least 10 successes and 10 failures can be expected in the sample. This can be verified by checking that np 10, and n(1 p) 10, where n is the number in the sample and p is the population proportion. ≥ − ≥ Identify n, the sample size. n = 900 Multiply n, the sample size, by p, the population proportion, to find the number of people that would be expected to read prink books exclusively. 900 • 0.37 = 333 Multiply n, the sample size, by (1 p) to find the number of people that would be expected to not exclusively read print books.− (1 )900 • − 0.37 = 567 Therefore, since np 10 and n(1 p) 10, the Large Samples condition is satisfied.≥ − ≥ The Big Populations condition requires that if the sample is collected without replacement, then the population size must be at least 10 times bigger than the sample. The population size can reasonably be assumed to be at least 10 times bigger than the sample. c. What is the standard error for this sample proportion? For a random sample of size n from a population with proportion p, the sampling distribution of the sample proportion has the following standard error. Be sure to use the decimal equivalent of the percentage given for p. SE = p(1 − p) n Identify the variables in the equation. p = 0.37 n = 900 Substitute and evaluate to find the standard error, rounding to three decimal places. SE = p(1 − p) n = 0.37(1 − 0.37) 900 = 0.016 Thus the standard error is .0.016 d. Complete this sentence, use your answers to fill in the blanks below. Remember the expected percentage of Americans who read print books exclusively in the sample is equal to the population percentage. Also, the standard error for the sample is the amount we expect our sample to be off by. Be sure to give both values in their percentage form. We expect % of Americans to read print books exclusively, give or take %.37 1.6 7/14/2019 M7 MyStatLab Assignment-Dylan Boccardo https://xlitemprod.pearsoncmg.com/api/v1/print/math 1/1 Student: Dylan Boccardo Date: 07/14/19 Instructor: Pamela Kimbrough Course: Statistics, Summer 2019 - B Term, Coordinator, Sec. B03 Assignment: M7 MyStatLab Assignment According to a poll, out of randomly selected smokers polled believed they are discriminated against in public life or in employment because of their smoking.927 1305 a. What percentage of the smokers polled believed they are discriminated against because of their smoking? b. Check the conditions to determine whether the CLT can be used to find a confidence interval. c. Find a 95% confidence interval for the population proportion of smokers who believe they are discriminated against because of their smoking. d. Can this confidence interval be used to conclude that the majority of smokers believe they are discriminated against because of their smoking? Why or why not? a. To find the percentage of successes in a sample, multiply the sample proportion by 100%. The sample proportion is the number of successes divided by the number of trials. To find the sample proportion of those who believed they are discriminated against because of their smoking, divide the number of smokers who believed they are discriminated by the sample size. The number of smokers who believe that they are discriminated against in public life or employment because of their smoking, or the number of successes, is .927 The sample size is .1305 Divide the number who feel discriminated against by the sample size, rounding to three decimal places. 927 1305 = 0.710 Thus, the sample proportion is . To find the percentage of those taking the poll who believed they are discriminated against because of their smoking, multiply by 100%.p 0.710 p %0.710(100%) = 71.0 Thus, % of those taking the poll believed they are discriminated against because of their smoking.71.0 b. To determine whether you can apply the CLT to find a confidence interval, three conditions must hold: the Random and Independent condition, the Large Sample condition, and the Big Population condition. The Random and Independent condition requires that the sample is collected randomly from the population, and observations are independent of each other. The sample can be collected either with or without replacement. The Random and Independent condition can be assumed to hold as it says in the problem statement that the sample was randomly collected, and it is reasonable to assume that responses are independent of each other. The Large Sample condition requires that the sample size, n, is large enough that the sample expects at least 10 successes and 10 failures. This can be verified by checking that and , where n is the sample size and is the sample proportion of successes.n ≥ 10p n ≥ 101 − p p Recall that . First calculate , rounding to the nearest integer.p = 0.710 np np = 1305(0.710) = 927 Calculate , rounding to the nearest integer.n 1 − p n 1 − p = 1305(1 − 0.710) = 378 The Large Sample condition holds, because and , which are both greater than or equal to 10.np = 927 n 1 − p = 378 The Big Population condition requires that if the sample is collected without replacement, then the population size must be much (at least ten times) bigger than the sample size. The Big Population condition holds, because the population of smokers is more than ten times .1305 Therefore, the conditions to determine whether you can apply the CLT to find a confidence interval all hold. c. While either technology or the formulas below can be used to calculate the 95% confidence interval for the proportion who believe they are discriminated against because of their smoking, in this problem, technology will be used. In the formulas below, m is the margin of error, is the sample proportion of successes, or the proportion of people in the sample with the characteristic of interest, n is the sample size, is a multiplier that is chosen to achieve the desired confidence level, and is the estimated standard error. p z * SEest , where and ± mp m = z SE * est SE =est p 1 − p n The 95% confidence level should be used for the confidence interval. Recall that . Enter the values into technology to find a 95% confidence interval for the proportion who believe they are discriminated against because of their smoking, rounding to three decimal places. p = 0.710 The 95% confidence interval is .( )0.686,0.735 d. Examine the confidence interval from part (c). Consider what it means to have a majority, and how the bounds of the confidence interval can be used to determine if the majority of smokers believe they are discriminated against because of their smoking. Note that to have a majority, the population proportion should be above 0.5. Note that if one is to be sure that the true population proportion represents a majority, the bounds of the confidence interval should both be above 0.5. Use this information to determine if one can conclude that the majority of smokers believe they are discriminated against because of their smoking. 7/14/2019 M6 MyStatLab Assignment-Dylan Boccardo https://xlitemprod.pearsoncmg.com/api/v1/print/math 1/1 Student: Dylan Boccardo Date: 07/14/19 Instructor: Pamela Kimbrough Course: Statistics, Summer 2019 - B Term, Coordinator, Sec. B03 Assignment: M6 MyStatLab Assignment Use technology to find the indicated area under the standard Normal curve. Include an appropriately labeled sketch of the Normal curve and shade the appropriate region. a. Find the probability that a z-score will be or less.2.28 b. Find the probability that a z-score will be or more.2.28 c. Find the probability that a z-score will be between and .− 1.7 − 1.07 a. Sketch a Normal curve and shade the area to the left of . The graph of the region to the left of is shown below.2.28 z = − 2.28 2.28 Use technology to find the area to the