1 Name: ____________________________ Torque and Static Equilibrium: PhET Lab Introduction: The term torque (τ, Greek letter tau) is given to the turning effect you observed when applying a force and...

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1 Name: ____________________________ Torque and Static Equilibrium: PhET Lab Introduction: The term torque (τ, Greek letter tau) is given to the turning effect you observed when applying a force and is a measurable quantity. To cause rotation, the twisting effect of a force depends on the magnitude of the force, and on the perpendicular distance between the point or axis of rotation and the line of force (called the lever arm or moment arm). The torque is defined as the product of the magnitude of the force, F, and the lever arm, l. We can also think of it as the perpendicular component of the force times the radial distance r between the axis of rotation and point at which the force is applied. Therefore, the magnitude of the torque can be found either way. As we discovered, the torque was greatest for a force exerted 90° to the lever arm (tangential force) and farthest from the axis of rotation. The quantity of torque decreased as the force was applied closer to the rotation point and no rotational effect was observed with the force (radial) applied to the end of the meter stick, when the line of action of the force passed through the axis of rotation. The meter stick simply exerts a force on you of equal magnitude and opposite direction. Newton's laws apply to rotational motion just as they do to translational motion. However, it is torque, not force which must be considered. A rigid body is in equilibrium when there is no change in the translational motion nor in the rotational motion. That is, the sum of the externally applied forces is zero, and the sum of the externally applied torques is zero. In this experiment, you will investigate torques needed to keep a body in rotational equilibrium. Mathematically, the conditions for equilibrium are thus: ∑ �⃗⃗� = 0 and ∑? = 0. Note that these are both vector sums, with the force usually have components in the xy-plane, with torque in the z direction (clockwise, counter clockwise). 2 Procedure: On your browser, go to https://phet.colorado.edu/ Click on “simulations” → “Physics” → “Balancing Act” → Download or run Static Equilibrium on a beam 1. In the menu, select the Balance Lab simulation. 2. Play with the sim and get used to it. Click on all the check boxes on the right to see what each of them does. Keep mass labels, forces from objects and ruler options checked for your simulations. Play with moving objects and applying different forces. 3. Besides the middle (permanent) support of the beam, there are two stationary supports on both sides of the beam. This is seen when the bottom switch is on the left side. You can use this option to place masses on the beam without moving it. 4. Once you are done placing your masses and want to check if there is balance (static equilibrium), you can remove the temporary supports by moving the buttom switch to right. In the example case below, there is no balance or static equilibrium and the system turns clockwise direction. https://phet.colorado.edu/ 3 5. When there is balance (or static equilibrium), the beam will not move or turn even after removing the supports. An example is shown below. PART A: 1. Make sure there are no masses on the beam and the ruler is active. 2. Place a 10 kg mass (m1) on the right side of the beam, 0.75 m away from the middle support. Record the mass and its position from the middle support (x1) in Data Table 1 below. 3. Place a 15 kg mass (m2) on the left side and adjust its position until static equilibrium is found. Record m2 and its position from the middle support (x2) in Data Table 1. 4. Now, calculate the torque (1) created by m1 around the middle support. Don’t forget that torque is related with force, not the mass. You will need to calculate the weight first. Calculation for torque 1 (1) including direction: 5. Calculate the torque created by m2 around the middle support. Calculation for torque 2 (2) including direction: Data Table 1 Mass m1 (kg) Position x1 Torque 1 Mass m2 (kg) Position x2 Torque 2 6. Draw the free body diagram of the system. Don’t forget to place all the forces on the beam including normal force from the middle support. Prove the static equilibrium with your calculations. 4 PART B: 1. Make sure there are no masses on the beam and the ruler is active. 2. Place a 10 kg mass (m1) and a 5 kg mass (m2) at two different positions on the right side of the beam. Record the masses (m1 and m2) and their positions from the middle support (x1 and x2) in Data Table 2 below. 3. Using a 20 kg mass (m3), find a location on the left side that will balance the beam. Record m3 and x3 in Table 2. 4. Now, calculate the torque (1) created by m1 and torque (2) created by m2 around the middle support. Calculation for torque 1 (1) and torque 2 (2)including direction: 5. Calculate the torque created by m3 around the middle support. Calculation for torque 3 (3) including direction: Data Table 2 Mass m1 (kg) Position x1 Torque 1 Mass m2 (kg) Position x2 Torque 2 Mass m3 (kg) Position x3 Torque 3 6. Draw the free body diagram of the system. Don’t forget to place all the forces on the beam including normal force from the middle support. Prove the static equilibrium with your calculations. 5 Questions: 1. Two forces produce the same torque. Does it follow that they have the same magnitude? 2. Give an example of a system in which the net torque is zero, but the net force is nonzero. 3. Give an example of a system in which the net force is zero, but the net torque is nonzero. 4. Explain why the masses are moved back and forth along a scale on a triple-beam balance.
Answered 1 days AfterJul 01, 2021

Answer To: 1 Name: ____________________________ Torque and Static Equilibrium: PhET Lab Introduction: The term...

Nupur answered on Jul 02 2021
147 Votes
Name…………………………
Objective:
To use the balance lab simulations and calculate the torques acting around the pivot point due to the masses placed on the beam. The objective also includes proving that the system rests in stati
c equilibrium.
Background Information:
There are two conditions that are required to be satisfied for static equilibrium.
1. Net force acting on the bodies must be zero.
             1
This condition represents the translational equilibrium, and therefore implies that Translatory acceleration is zero.
2. Net Torque acting on the bodies is zero.
                         2
The second equilibrium condition implies that under equilibrium, net external torque to cause rotation about any axis is zero i.e. angular acceleration is zero.
Therefore, for a system to be in static equilibrium, both linear and angular acceleration is required to be zero.
Torque represents the twisting force that acts upon the body and causes its rotation about a pivot point or the axis of rotation. To cause rotation, the twisting effect of a force depends on the magnitude of the force, and on the perpendicular distance between the point or axis of rotation and the line of force (called the lever arm or moment arm). Torque can also be calculated by product of the perpendicular component of the force and the radial distance r between the axis of rotation and point at which the force is applied.
τ = F*r
PART A
Data Table 1
    Mass (m1)
    Position (x1)
    Torque (τ1)
    10
    0.75
    73.5 (clockwise), -ve
    Mass (m2)
    Position (x2)
    Torque (τ2)
    15
    0.5
    73.5 (anti-clockwise), +ve
Reasoning:
Torque is related to force but in this problem we are given only mass and perpendicular distance. It is, thus, required that we calculate force exerted by the body due to its weight. The weight force is simply calculated as F = mg, where g represents the acceleration due to gravity (9.8 ms-2).
The two bodies of mass m1 and m2 exert a force F1 and F2, respectively, at their positions in downward direction, under the effect of center of gravity. In addition to these two...
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