Kinetics, the study of unbalanced forces causing motion, can be analyzed by three methods: inertia force or torque (dynamic equilibrium), work and energy, and impulse and momentum.Consider the...

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Kinetics, the study of unbalanced forces causing motion, can be analyzed by three methods: inertia force or torque (dynamic equilibrium), work and energy, and impulse and momentum. Consider the following as you complete your assignment: For linear motion the inertia force is · Equal to ma · Acting through the center of gravity · Opposite in direction to the acceleration For rotational motion the inertia torque is · Equal to C · Opposite in direction to the angular acceleration For a plane motion problem such as a rolling cylinder, try to · Equate or relate linear acceleration to angular acceleration. · Take moments at the rolling point of contact with the surface. Questions 13–1. Determine the acceleration of the 150-lb block in Figure P13–1 if the coefficient of kinetic friction is 0.4. 13–3. A 130-kg cart is accelerated horizontally by a 250-N force pulling at an angle of 20° above horizontal. Neglecting rolling resistance, determine the acceleration of the cart. 13–7. At what maximum acceleration rate can a 500-N test-strength cable lift a 40-kg mass? 13–8. What force does a 180-lb man exert on the floor of an elevator that is moving downward and decelerating at 15 ft/s^2? 13–20. The coefficient of kinetic friction for mass B in Figure P13–20 is 0.25. Determine the acceleration of mass A if it has a mass of (a) 30 kg and (b) 50 kg. 13–36. A 1000-kW generator has a 3500-lb rotor that is accelerated from rest to 3600 rpm in 10 seconds. Determine the torque required. Assume the rotor to be a solid cylinder 40 in. in diameter. 13–41. A 150-mm-diameter shaft with a mass of 20 kg is rotating at 900 rpm. A pulley mounted on the shaft has a mass moment of inertia of 0.15 kg ⋅ m^2. If the shaft and the pulley coast to a stop due to a tangential frictional force of 8 lb at the outer radius of the shaft, determine the time required.
Answered 2 days AfterFeb 15, 2023

Answer To: Kinetics, the study of unbalanced forces causing motion, can be analyzed by three methods: inertia...

Baljit answered on Feb 15 2023
37 Votes
Questions
13–1.
Determine the acceleration of the 150-lb block in Figure P13–1 if the coefficient of kinetic friction is 0.4.
Answer:--
A force of 90lbs at a an
gle of 45degre downward the horizontal
F1x = 90 cos45 = 63.64 lbs
F2y = 90 sin45 = 63.64 lbs
Other force 60 lbs upwards at angle of 30 degrees to horizontal
so horizontall component
F2x = 60cos30 = 51.96 lbs
F2y = 60 sin30 = 30 lbs upwards
and thers is two other forces are also there one is normal force N and other its weight 150lb . Normal force N s in upward direction and weight is in downward direction .
there will be a friction force in horizontal µN in oppsite direction of force .
so now in vertical direction
N + 30 = 150 + 63.64
N = 183.64 lbs
in horizontal direction:
F1x +F2x - µN = Ma
63.64 + 51.96 - 0.4 X 183.64 = Ma
Ma = 42.14
a = 42.14/(150 X g) = 0.281g = 0.281 X 32.2 = 9.05 ft /sec2
13–3.
A 130-kg cart is accelerated horizontally by a 250-N force pulling at an angle of 20° above horizontal. Neglecting rolling resistance, determine the acceleration of the cart.
Answer:-
Free Body diagram of the Cart is as following
Now apply force equilibrium on Horizontal Direction.
i.e Fx-ma=0
ma=250cos20
a=250cos20/m=250 cos20/130=1.8 m/sec2
13–7.
At what maximum acceleration rate can a 500-N test-strength cable lift a 40-kg mass?
Answer:-
Free Body diagram of scenerio is as following
Now m=40Kg
W=m*g=40*9.81=392.4N
Apply Force equilibrium in Vertical Direction
T-W-ma=0
a=(T-W)/m=(500-392.4)/40=2.69 m/sec2
13–8.
What force does a 180-lb man exert on the floor of an elevator that is moving downward and decelerating...
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