Let -2x2 + 3x for x 0. According to the definition of the derivative, to compute f'(0), we need to compute the left-hand limit lim 2х-3 which is and the right-hand limit lim 6x which is 0 We conclude...

Let<br>-2x2 + 3x for x < 0,<br>| 6x² – 2<br>f(x)<br>for x >0.<br>According to the definition of the derivative, to compute f'(0), we need to compute the left-hand limit<br>lim<br>2х-3<br>which is<br>and the right-hand limit<br>lim<br>6x<br>which is 0<br>We conclude that f'(0) is undefined<br>Note: If a limit or derivative is undefined, enter 'undefined' as your answer.<br>

Extracted text: Let -2x2 + 3x for x < 0,="" |="" 6x²="" –="" 2="" f(x)="" for="" x="">0. According to the definition of the derivative, to compute f'(0), we need to compute the left-hand limit lim 2х-3 which is and the right-hand limit lim 6x which is 0 We conclude that f'(0) is undefined Note: If a limit or derivative is undefined, enter 'undefined' as your answer.

Jun 11, 2022

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Let -2x2 + 3x for x 0. According to the definition of the derivative, to compute f'(0), we need to compute the left-hand limit lim 2х-3 which is and the right-hand limit lim 6x which is 0 We conclude...

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