Suppose you are a lawyer representing a Hispanic individual in a criminal trial. Twelve jurors are randomly selected by the state from a population that you know to be 55% Hispanic. a. How many jurors...

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Suppose you are a lawyer representing a Hispanic individual in a criminal trial. Twelve jurors are randomly selected by the state from a population that you know to be 55% Hispanic.
a. How many jurors would you expect to be Hispanic?
b. The select process produces a jury with 2 Hispanic individuals What proportion of the jury is Hispanic? (Enter your answer as a decimal, rounded to four decimal places)
c. Use the binomial distribution and find the probability that 2 or fewer jurors would be Hispanic.
d. Create a graph of the distribution with the area corresponding to the previous answer shaded in. Choices for creating a graph include: Excel, Binomial Distribution Calculator (in resources menu), TI-84 (take a pic), hand drawn, other software, websites. Upload your finished graph below.
e. Use Statistics to make an argument to the court on behalf of your client. Structure your essay as a paragraph that contains the following:
Your Honor,
Explain why random sampling in this situation of juror selection relates the expected sample proportion to the population proportion.
Compare the expected value to the actual sample proportion.
Show that the requirements for a binomial experiment are met in this situation, implying that the binomial distribution can be used.
Identify the values for n,p, and x for this situation
Interpret the answers to parts c. and d. and submit them as evidence.
Use this to argue that the juror selection was likely to be random or not likely to be random (depending on your answer to part c).
Request a new jury be selected or accept the selected jury (depending on your answer to part c)
Respectfully,


[Your Name]

Answered Same DayMar 01, 2021

Answer To: Suppose you are a lawyer representing a Hispanic individual in a criminal trial. Twelve jurors are...

Pooja answered on Mar 01 2021
133 Votes
Question 1)
N=12
P=55%
a)
E(X) = np = 12*55% = 6.6
b)
P( X = 2 ) = ( 12 2 ) * ( 0.55^2) * ( 1
- 0.55 )^10
=BINOM.DIST(2,12,0.55,FALSE)
= 0.006798208
c)
P(X<=2) = P(X=0) + P(X=1) + P(X=2)
P(X<=2) = BINOM.DIST(2,12,0.55,TRUE)
P(X<=2) = 0.0079
d)
    X
    P(X=x) = binom.dist(x,12,.55,false)
    0
    6.89525E-05
    1
    0.001011304
    2
    0.006798208
    3
    0.027696403
    4
    0.076165109
    5
    0.148945102
    6
    0.212384682
    7
    0.222498238
    8
    0.169963932
    9
    0.092326087
    10
    0.033852898
    11
    0.007522866
    12
    0.000766218
Question 2)
(1) In the process of simple random sampling, each unit of the population has equal and independent answers being included in the...
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